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SCORPION-xisa [38]
3 years ago
11

Find the mean (average)the data set below?2 18 28 54' 5'10'20​

Mathematics
1 answer:
ehidna [41]3 years ago
7 0

Answer:

11.5

Step-by-step explanation:

You add up all the values which is 92 and divide by 8 since there are 8 values. You get 11.5

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erastovalidia [21]

Answer:

Given no. of persons owned laptop = 76

Total of no. of students owned + Total of no. of students dont have owned laptop given = 155

No. of students dont have laptops = 155 - 76 = 79

So then the total no. of no laptops = 79 + 17 = 96(ans)

8 0
3 years ago
Determine which of the following angle measures are correct. Select all the apply
sammy [17]

Answer:

number 2 and 4

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
REALLY NEED HELP AND WILL MARK YOU AS BRAINLIEST!
katen-ka-za [31]
First, let’s break this down. What exactly are we looking at here? Well, Daisy measured the heights of 20 plants (in cm). The table, under Frequency, shows the # of plants that fit within a certain height range, shown on the left under Height of Plants (h).

Now, it says to take the midpoints of each group to figure out an estimate of the mean height. To find the mean, you add up all the totals and divide it by the # of items. So, let’s go through each row.

Midpoint of 0-10 is 5, and Frequency is 1, so that gives us 5.
Midpoint of 10-20 is 15, Frequency is 4, and 15x4=60.
We continue this with the other rows by finding the midpoint & multiplying the midpoint by the frequency (if the frequency is greater than 1). This gives us the numbers:

175 (25x7)
70 (35x2)
135 (45x3)
165 (55x3)

Now, we add these all together.
5+60+175+70+135+165=610

Finally, we divide 610 by the # of items (remember, there are 20 plants so we divide by 20) and 610/20 is 30.5.


FINAL ANSWER:

Thus, if I calculated correctly (which I hope I did lol), our estimate for the mean height of a plant is 30.5 cm!
4 0
3 years ago
Which expression is equivalent to am ÷ an?
posledela
I'm not 100% sure if this is what you're looking for, but am/an is equivalent to that
6 0
3 years ago
t^2+4t+4 t^2-2t+1 Consider the parametric curve a. Find points on the parametric curve where the tangent lines are vertical. b.
kondaur [170]

Answer:

a) t = 1, b)  t = -2, c) Concave upward: (-\infty, 1). No intervals being concave downward.

Step-by-step explanation:

a) Tangent line is vertical if slope is undefined, whose points are associated with discontinuities of the function. Rational functions have discontinuities associated with the denominator:

f(t) = \frac{t^{2}+4\cdot t +4}{t^{2}-2\cdot t + 1}

By factorizing each component, the function is re-arranged as:

f(t) = \frac{(t+2)^{2}}{(t-1)^{2}}

There is no avoidable discontinuities. The only point where tangent line is vertical is t = 1.

b) Tangent line is horizontal if slope is equal to zero, whose point is associated to the points that makes function equal to zero. Rational functions have horizontal tangent lines if numerator is equal to zero and denominator is different to zero. Hence, the only point where tangent line is  horizontal is t = -2.

c) An interval is concave upward if exist an absolute minimum inside, which can be found by the help of the First and Second Derivative Tests.

f'(t) = \frac{2\cdot (t+2)\cdot (t-1)^{2}-2\cdot (t-1)\cdot (t+2)^{2}}{(t-1)^{4}}

f'(t) = 2\cdot (t+2)\cdot (t-1)\cdot \left[\frac{t-1-t-2}{(t-1)^{4}}\right]

f'(t) = -\frac{6\cdot (t+2)\cdot (t-1)}{(t-1)^{4}}

f'(t) = -\frac{6\cdot (t+2)}{(t-1)^{3}}

The only critical point is:

-6\cdot (t+2) = 0

t = -2 (which coincides with the result of point b)

f''(t) = -6\cdot \left[\frac{(t-1)^{3}-3\cdot (t-1)^{2}\cdot (t+2)}{(t-1)^{6}}\right]

f''(t) = -6\cdot \left[\frac{1}{(t-1)^{3}}-\frac{3\cdot (t+2)}{(t-1)^{4}}  \right]

The value associated with the critical point is:

f''(-2) = \frac{2}{9}

Which means that critical point is an absolute minimum, and, consequently, the interval that is concave upward is (-\infty, 1). There is no absolute maximums and, therefore, there is no interval that is concave downward.

7 0
4 years ago
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