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Murrr4er [49]
3 years ago
8

How do I solve this???

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
6 0
M equals 56 and b equals 30
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Solve for x. (have to add extra letters so the question works)
zloy xaker [14]

Answer:

x=11°

Step-by-step explanation:

-Sum of angles of a triangle should alway be 180 degrees

35+110+2+3x=180

-Add all known values

147+3x=180

-Subtract 147 from both sides

3x=33

-Isolate x by divind both sides by 3

x=11°

5 0
3 years ago
Free Points!!! (25pts)
IgorC [24]

2-1=1

1x275=275

275+1=276

276/2=138



8 0
3 years ago
Read 2 more answers
Krista's mom has told her she needs to make the pen ½ the size that she had planned (5 feet long by 4 ½ feet wide). What will th
saw5 [17]

Answer:

1. area of new pen = 11 \frac{1}{4} ft^{2}

2. i. 5 feet by 2\frac{1}{4} feet

ii. 2 ½ feet by 4 ½ feet

Step-by-step explanation:

The size of the pen as planned = 5 ft long by 4 ½ ft wide

Area of the pen = length x width

                           = 5 x 4 ½

                           = 5 x \frac{9}{2}

Area of the pen = \frac{45}{2}

                           = 22 ½ ft^{2}

But, Krista has to make the pen ½ the size of planned. So that;

area of new pen = ½ x 22 ½

        = ½ x \frac{45}{2}

        = \frac{45}{4}

        = 11 \frac{1}{4}

area of new pen = 11 \frac{1}{4} ft^{2}

The area of the new pen would be 11 \frac{1}{4} ft^{2}.

The possible values she could use are:

i. 5 feet by 2\frac{1}{4} feet

ii. 2 ½ feet by 4 ½ feet

6 0
3 years ago
How do yo slove the problem
maksim [4K]
4) In triangle, angle opposite to perpendicular is 90-60 = 30
So, tan Ф = P/B
tan 30 = a / 6
1/√3 = a/6
a = 6/√3
a = 2√3

Now, cosФ = B/H
cos 30 = 6/b
√3/2 = 6/b
b = 6*2/√3
b = 12/√3
b = 4√3

In short, Your Answer would be a = 2√3 and b = 4√3

Hope this helps!
6 0
3 years ago
Read 2 more answers
Find lim x->2 for f(x)=
TiliK225 [7]

LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)

<h3>What is the limit of a function ?</h3>

The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.

It is given that

lim x->2 for f(x)

\lim_{x \rightarrow 2^-}f(x) = \lim_{x\rightarrow 2^+}f(x)

f(x) = 2x+1 x ≤2

f(x)= x² , x >2

When both the function tends to 2

Left Hand Limit

f(x) = 2 *2 +1

f(x) = 5

Right Hand Limit

f(x) = x² ,

f(x) = 4

LHL in not equal to RHL , Therefore the limit does not exists.

To know more about Limit of a Function

brainly.com/question/7446469

#SPJ1

8 0
2 years ago
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