Answer:
5 english students in each team
Step-by-step explanation:
So there are multiple ways to do this, you could do trial and error or you could factor out common numbers between the two.
Through trial and error, the lowest possible number of groups that could be divided between the number of students whilst still being able to maintain a whole # was 16 groups
- 128 math students ÷16 groups = 8 math students/group
- 80 english students ÷ 16 groups = 5 english students/group
The other way to solve this is to factor out common numbers between the two:
The answer is negative twenty five. By the way, if that is you in the picture, you are beautiful.
Answer:
2856
Step-by-step explanation:
This question is a little unclear. 6 times 17 times 28 is equal to 2856 if that is what you are trying to ask.
K^2-5k-50
(k-10)(k+5)
This is because k*k=k^2 (your first term), 5k-10k=-5k (your second term) and -10*5=-50 (your last term).
Distribute to check.