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Sati [7]
3 years ago
13

Find the Parametric equation of the line, which passes through the points: a=(1,2,3), b=(2,0,-4)

Mathematics
1 answer:
skad [1K]3 years ago
6 0

Answer:

(x,y,z) = (1+s, 2-2s,3-7s)

Step-by-step explanation:

Given that a line in three dimension passes through two points a and b

We have equation of the line passing through two points

(x_1,y_1,z_1) \\(x_2,y_2,z_2) is

\frac{x-x_1}{x_2-x_1} =\frac{y-y_1}{y_2-y_1} =\frac{z-z_1}{z_2-z_1}

Substitute for the two points and equate to s

\frac{x-1}{2-1} =\frac{y-2}{0_2} =\frac{z-3}{-4-3}=s

Simplify to write

\frac{x-1}{1} =\frac{y-2}{-2} =\frac{z-3}{-7} =s\\x=1+s:  y= 2-2s:   z=3-7s

Thus parametric form is

(x,y,z) = (1+s, 2-2s,3-7s)

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Answer:

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Step-by-step explanation:

Bouncing of a ball can be expressed by a Geometric Progression. The function for the given scenario is:

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The general formula for the geometric progression modelling this scenario is:

f(n)=f_{0}(r)^{n}

Here,

f_{0} represents the initial height i.e. the height from which the object was dropped.

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Comparing the given scenario with general equation, we can write:

f_{0} = 9

r = 0.7 = 70%

i.e. the ball was dropped from the height of 9 feet initially and it bounces back to 70% of its previous height every time.

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Answer:

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Step-by-step explanation:

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