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Deffense [45]
3 years ago
9

I don't under this Anyone know the answer ?

Mathematics
1 answer:
user100 [1]3 years ago
7 0
X=5
Y=-23
Hope it helps

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Find the equation of the line that is perpendicular to y=3/4x-3 and passes through the point (3,-2)
morpeh [17]

Answer:

Step-by-step explanation:

perp. -4/3

y + 2 = -4/3(x - 3)

y + 2 = -4/3x + 4

y = -4/3x + 2

4 0
3 years ago
Complete the square to solve the equation below. check all that apply.<br><br> x^2 + 8x - 1 = 19
Andreas93 [3]
X=-10,x=2.I hope this helps.
8 0
2 years ago
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By copying and completing the working below, work out 3 + 1 16 Give your answer as a fraction in its simplest form.
Ksenya-84 [330]

Answer:

Assuming the question is:  3 + 1 16  [I see no "working below."

Step-by-step explanation:

3 + 1 16

48/16 + (16/16 + 1/16)  [Make all numbers into fractions using 16 as the denominator.  E.g. 48/16 = 3.

Add:  48/16 + (16/16 + 1/16)

  (48+16+1)/16

=63/16

[Also equal to 3 15/16]

7 0
3 years ago
Someone explain this?
nadya68 [22]

5\sqrt{96}.
I converted it into decimal form with a calculator and got approximately 48.9898

And if you round that, you will get the 49, which fits the inequality of

45<  5\sqrt{96} < 50 since it becomes 45 < 49 < 50 which is true

8 0
2 years ago
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true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp
Goshia [24]

Answer:

\mu = 114, \sigma = 40

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation for the sampling distribution would be:

\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

\mu = 114, \sigma = 40

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation for the sampling distribution would be:

\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4

So then the answer is TRUE

6 0
3 years ago
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