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svlad2 [7]
2 years ago
8

Graph the image of this figure after a dilation with a scale factor of 1/2 centered at the point (−3, 0).

Mathematics
1 answer:
lyudmila [28]2 years ago
7 0

The vertices of the image of dilation are (4, 2), (-1, 2) and (3, 4)

<h3>How to graph the dilated image?</h3>

The given parameters are:

Center, (a, b) = (-3, 0)

Scale factor, k = 1/2

The vertices of the figure are

(5,4), (-5, 4) and (3,8)

The rule of dilation is represented as:

(x, y) ⇒ (k(x -a), k(y -b))

So, we have:

Point (5,4)

(x, y) ⇒ (1/2(5 + 3), 1/2(4 -0))

(x, y) ⇒ (4, 2)

Point (-5,4)

(x, y) ⇒ (1/2(-5 + 3), 1/2(4 -0))

(x, y) ⇒ (-1, 2)

Point (3,8)

(x, y) ⇒ (1/2(3 + 3), 1/2(8 -0))

(x, y) ⇒ (3, 4)

So, the vertices of the image of dilation are (4, 2), (-1, 2) and (3, 4)

See attachment for the image

Read more about dilation at:

brainly.com/question/3457976

#SPJ1

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=========================================

Work Shown:

You can use point slope form by plugging in m = -5 and (x_1, y_1) = (7,-3)

So,

y - y_1 = m(x - x_1)\\\\y - (-3) = -5(x - 7)\\\\y + 3 = -5(x - 7)\\\\y + 3 = -5x + 35\\\\y + 3-3 = -5x + 35-3 \text{ subtract 3 from both sides} \\\\y = -5x + 32\\

---------------

Or you could use y = mx+b to solve for the value of b

Plug in m = -5, and (x,y) = (7,-3)

y = mx+b\\\\-3 = (-5)(7)+b\\\\-3 = -35+b\\\\-3+35 = -35+b+35\\\\32 = b\\\\b = 32\\\\

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