2 gallons * $2.58 per gallon = $5.16 expenses (total spent)
2 gallons * 16 cups = 32 total servings
32 cups * $0.75 per cup = $24 gross revenue (total income)
$24 - $5.16 = $19.84 net revenue (profit)
Given a Venn diagram showing the number of students that like blue uniform only as 32, the number of students that like gold uniform only as 25, the number of students that like blue and gold uniforms as 12 and the number of students that like neither blue nor gold uniform as 6.
Thus, the total number of students interviewed is 75.
Recall that relative frequency of an event is the outcome of the event divided by the total possible outcome of the experiment.
From the relative frequency table, a represent the relative frequency of the students that like gold but not blue.
From the Venn, diagram, the number of students that like gold uniform only as 25, thus the relative frequency of the students that like gold but not blue is given by
Therefore,
a = 33% to the nearest percent.
Similarly, from the relative frequency table, b represent the relative frequency of the students that like blue but not gold.
From
the Venn, diagram, the number of students that like blue uniform only
as 32, thus the relative frequency of the students that like gold but
not blue is given by
Therefore,
b = 43% to the nearest percent.
Answer:
10
Step-by-step explanation:
let the number be n then half the number is n , so
n + 69 = 74 ( subtract 69 from both sides )
n = 5 ( multiply both sides by 2 to clear the fraction )
n = 10
Thus the number is 10
18 2/5 = 92/5 = 18.4 as a decimal;
Answer:
b+6
Problem:
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Step-by-step explanation:
We are given (b+c)/2=8 and d=3b-4.
We are asked to find (c+d)/2 in terms of variable, b.
We need to first solve (b+c)/2=8 for c.
Multiply both sides by 2: b+c=16.
Subtract b on both sides: c=16-b
Now let's plug in c=16-b and d=3b-4 into (c+d)/2:
([16-b]+[3b-4])/2
Combine like terms:
(12+2b)/2
Divide top and bottom by 2:
(6+1b)/1
Multiplicative identity property applied:
(6+b)/1
Anything divided by 1 is that anything:
(6+b)
6+b
b+6