5 red, 3 yellow, and 2 blue....for a total of 10 marbles
P(first one being blue) = 2/10 which reduces to 1/5
not replaced
P(second one is blue) = 1/9...because u already pick a blue, meaning there is only 1 left, and there is one less marble, so there is a total of 9 marbles.
P(both events happening) = 1/5 * 1/9 = 1/45 <==
There should be sixteen branches. There are four possible suits for the first card, hearts, diamonds, clubs, spades. Then each of those four branches has four branches for the second card drawn. 4*4 = 16.
The third quartile of this data set is B. 24.
Divide both sides by 36
6/36 = p
1/6 = p
a) f(4) = 3*4 - 4
= 8
b) h(-3) = 5 - ( - 3)
= 5 + 3 = 8
c) h(4) - f(-5) = 1 + ( -19)
= -18
have a nice day <3
