Answer:
±2√21.
Step-by-step explanation:
First, you break 84 down into √4⋅√21.
That is equal to ±2√21.
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Answer:
Option 4: 1.25/2π = 32/2πr
Step-by-step explanation:
Arc length = (theta/2pi) × 2pi × r
32 = (1.25/2pi) × 2pi × r
1.25/2pi = 32/(2pi × r)
Answer: When t = 4.25 R(t) = D(t)
This tells you that at 4.25 seconds into their flights, both the Rocket and the Drone were at a height of 20 feet.
Step-by-step explanation: The point where the two graphed lines cross is where the values are equal.
The Drone has been hovering at 20 feet between 2 and 5 seconds. The Rocket passed through that height for a brief (millisecond) time as it was falling back to the ground.
Without grid lines it is my best estimation (using a ruler to create a verticla line from the intersection of the lines to the time scale) that t = 4.25. It is between 4 and 4.5 seconds.
Answer:
Step-by-step explanation:
B) the stone hits the water within the first 2 seconds. Because the stone drops at the speed of 88 feet/second, and 88 x 2 is 176. but the bridge is only 135 feet tall.
so,
88 feet/second
176 feet/2 seconds
135 feet means that it reached the river within 2 seconds. it reached the river in 1.545 seconds
