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Sever21 [200]
2 years ago
15

Two segments tangent to a circle from the same external point are __________.

Mathematics
2 answers:
horsena [70]2 years ago
7 0
The answer is letter D.

<span>Two segments tangent to a circle from the same external point are congruent, meaning they have the same length.

</span>

<span>Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.</span>

8_murik_8 [283]2 years ago
5 0
The answer is D.congruent.
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What is an simplified expression for 8a-(-3-5a)-2a?
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Answer:

The answer is 11a+3

Step-by-step explanation:

Simplify the terms.

8a+3+5a-2a

Combine like terms.

8a+5a-2a=11

11a+3

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Allison owns a food truck that sells tacos and burritos. She only has enough ingredients to make 98 tacos or burritos.Write an i
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2 years ago
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12345 [234]

Answer: The third one is the correct answer

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You are given the following information obtained from a random sample of 5 observations. 20 18 17 22 18 At 90% confidence, you w
Margaret [11]

Answer:

a

  The null hypothesis is  

         H_o  : \mu  =  21

The Alternative  hypothesis is  

           H_a  :  \mu<   21

b

     \sigma_{\= x} =   0.8944

c

   t = -2.236

d

  Yes the  mean population is  significantly less than 21.

Step-by-step explanation:

From the question we are given

           a set of  data  

                               20  18  17  22  18

       The confidence level is 90%

       The  sample  size  is  n =  5  

Generally the mean of the sample  is  mathematically evaluated as

        \= x  =  \frac{20 + 18 +  17 +  22 +  18}{5}

       \= x  =  19

The standard deviation is evaluated as

        \sigma =  \sqrt{ \frac{\sum (x_i - \= x)^2}{n} }

         \sigma =  \sqrt{ \frac{ ( 20- 19 )^2 + ( 18- 19 )^2 +( 17- 19 )^2 +( 22- 19 )^2 +( 18- 19 )^2 }{5} }

         \sigma = 2

Now the confidence level is given as  90 %  hence the level of significance can be evaluated as

         \alpha = 100 - 90

        \alpha = 10%

         \alpha =0.10

Now the null hypothesis is  

         H_o  : \mu  =  21

the Alternative  hypothesis is  

           H_a  :  \mu<   21

The  standard error of mean is mathematically evaluated as

         \sigma_{\= x} =   \frac{\sigma}{ \sqrt{n} }

substituting values

         \sigma_{\= x} =   \frac{2}{ \sqrt{5 } }

        \sigma_{\= x} =   0.8944

The test statistic is  evaluated as  

              t =  \frac{\= x - \mu }{ \frac{\sigma }{\sqrt{n} } }

substituting values

              t =  \frac{ 19  - 21 }{ 0.8944 }

              t = -2.236

The  critical value of the level of significance is  obtained from the critical value table for z values as  

                   z_{0.10} =  1.28

Looking at the obtained value we see that z_{0.10} is greater than the test statistics value so the null hypothesis is rejected

6 0
3 years ago
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