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IRINA_888 [86]
1 year ago
5

What is the first step you would take to solve the equation ?

Mathematics
1 answer:
Natalija [7]1 year ago
5 0

Like terms are those terms that are having the same variables, also the variables are of the same order as well. The first step to solving an equation is to rearrange the like terms.

<h3>What are Like terms?</h3>

Like terms are those terms that are having the same variables, also the variables are of the same order as well.

for example, 25x and 5x are like terms; 30xy and 7xy are like terms, 9x³ and 4x² are not like terms, etc.

To solve an equation the first step is to rearrange the equation such that like terms are together.

Hence, the first step to solving an equation is to rearrange the like terms.

Learn more about Like Terms:

brainly.com/question/2513478

#SPJ1

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A rectangular school banner has a length of 36 inches and a width of 52 inches. A sign is made that is similar to the school ban
zalisa [80]

Answer:

<u>4212 : 1573</u> is the ratio.

Step-by-step explanation:

Given:

Length of rectangular school banner is 36 inches and width is 52 inches.

And, the sign made is similar to banner.

The sign's length is 22 inches.

Now, we have to find the ratio of the area of the banner to the area of the sign.

So, we have dimensions of rectangular school banner:

Length = 36 inches.

Width = 52 inches.

But, we have only length of sign:

Length = 22 inches.

Now, we have to find the width of sign by using cross multiplication method:

Let the width of sign be x.

<em>As, sign is similar to banner.</em>

So, if 36 inches is equivalent to 52 inches.

Then, 22 inches is equivalent to x.

\frac{36}{52} =\frac{22}{x}

<em>By cross multiplying we get:</em>

<em />36x=1144<em />

<em>Dividing both sides by 36 we get:</em>

x=31\frac{7}{9} .

<em>Hence, the width of sign is </em>31\frac{7}{9}<em> inches.</em>

Now, we find the area of banner and the area of sign by putting formula:

Area of banner = length × width.

Area\ of\ banner=36\times 52

Area\ of\ banner=1872\ square\ inches.

Now, area of sign:

Area\ of\ sign=length\times width\\\\Area\ of\ sign=22\times 31\frac{7}{9} \\\\Area\ of\ sign=22\times \frac{286}{9} \\\\Area\ of\ sign=\frac{6292}{9} \ square\ inches.

Now, to get the ratio of the area of the school banner to the area of the sign:

1872:\frac{6292}{9}

=\frac{1872}{\frac{6292}{9} } \\\\=\frac{16848}{6292}

<em>On simplifying we get:</em>

=\frac{4212}{1573}

=4212:1573.

Therefore, the ratio of the area of the school banner to the area of the sign is 4212:1573.

8 0
3 years ago
During the first six months of operation, Abdoul's lemonade stand made a profit of $50 per month. In the next three months it ha
MrMuchimi

profit, p = 6 × $50 = $300

losses, l = 120 + 30 + 200 = $350

overall = p - l = -$50

loss of $50

4 0
3 years ago
A+46=-114<br><br> plz show how u got the answer
Soloha48 [4]

Answer:

a = 160

Step-by-step explanation:

a + 46 = -114

a + 46 - 46 = -114 - 46

a = 160

8 0
3 years ago
Write the standard equation of the circle shown.
zysi [14]

Answer:

b

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ← r is the radius

The circle shown is centred at the origin and has a radius of 5, thus

x² + y² = 5² ⇒ x² + y² = 25 → b

4 0
3 years ago
Solve 12|x|−7=8. Does anyone know how to do this?<br>​
Travka [436]

Answer:

8+8=16/12

x=16/12, 4/3

4 0
3 years ago
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