Let that be
Two vertical asymptotes at -1 and 0
If we simply
- Denominator has degree 2
- Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
- But there should be a x intercept at -3 so one zeros should be -3
Find a equation
Find zeros
Horizontal asymptote
So our equation is
Graph attached
1) 7000+300+10+3
2) 900,000+90,000+400+40+6
3) 600+80+2
4)30,000+7000+900+10+1
5)3,000,000+900,000+40,000+1,000+400+70+7
6)8000+400+70+4
7)700+70+2
8)30,000+7000+200+80+2
9)700,000+30,000+5,000+800+10+1
10)40,000+6000+400+40+9
11)5000+8000+70+2
12)5,000,000+700,000+50,000+8,000+900+40+5
13)5,000,000+900,000+90,000+8,000+800+90+0
14)300+70+7
15)300,000+20,000+3,000+200+40+8
Answer:
x=129
Step-by-step explanation:
180-51=129
Answer:
Symmetric point: x = -1; (-1, 5)
Minimum of f: None; approaches -∞.
Maximum of f: y = 5.
Is f(x) a one-to-one: No, it fails the horizontal line test and is not injective.
Increasing from: -∞ to -1; (-∞, -1)
Decreasing from: -1 to ∞. (-1, ∞)
Answer:
D- HM
Step-by-step explanation:
A ray has one point and one side that goes on forever. We see this expressed with HM
HK is a line
HM is a ray
