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sveticcg [70]
4 years ago
9

Sharif's white ball rolled 143 centimeters in 4 seconds and her green ball rolled 112 centimeters in 3 seconds. Which ball rolle

d at a greater rate of speed?
Mathematics
2 answers:
boyakko [2]4 years ago
5 0

Answer:

The green ball because even though that the white ball rolled 143 centimeters, the green ball rolled faster than the white one. Hope this helped you. don't bother with brainly. I always fail my stuff when I ask for help.

Step-by-step explanation:

Feliz [49]4 years ago
3 0

Answer:

  the <em>green</em> ball

Step-by-step explanation:

The rate in cm/s is found by dividing the distance (cm) by time (s). The speeds are ...

  white ball speed = (143 cm)/(4 s) = 35 3/4 cm/s

  green ball speed = (112 cm)/(3 s) = 37 1/3 cm/s

The green ball rolled faster.

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A student’s construction of the perpendicular bisector of is shown below. What is the student’s error?
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The student did not make the opening of each arc drawn from S and T greater than half the length of the line ST. When drawing a perpendicular bisector, the arcs should go past the center of the line segment.
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3 years ago
16. A negative number x a negative number is always positive. *<br> true<br> false<br> nositi
xenn [34]

Answer:

True.

Step-by-step explanation:

I don't know the explanation behind any of it, but a negative number, when multiples by another negative number, is always positive.

3 0
3 years ago
A man enters a tall tower, needing to know its height. he notes that a long pendulum extends from the ceiling almost to the floo
myrzilka [38]
A man enters a tall tower, needing to know its hieght. He notes that a long pendulum extends from the ceiling almost tothe floor and that its period is 15.5s. (a) How tall isthe tower? (b) If this pendulum is taken to the Moon,where the free-fall acceleration is 1.67m/s2, what isthe period there?T=15.5s(a) L=T2g/4π<span>2</span>
3 0
4 years ago
Which of the following is equivalent to 18 minus StartRoot negative 25 EndRoot? 5i 18 – 5i 18 + 5i 23
LuckyWell [14K]

Answer:

Step-by-step explanation:

18-\sqrt{-25}=18-\sqrt{i^{2}*5^{2}}\\\\=18-5i

3 0
3 years ago
Read 2 more answers
During the 7th examination of the Offspring cohort in the Framingham Heart Study there were 1219 participants being treated for
Lunna [17]

Answer:

95% confidence interval for the proportion of people in the population being treated for hypertension is [0.3293 , 0.3607].

Step-by-step explanation:

We are given that during the 7th examination of the Offspring cohort in the Framing ham Heart Study, there were 1219 participants being treated for hypertension and 2,313 who were not on treatment.

So, the sample proportion is :  \hat p = x/n = 1219/3532 = 0.345

Firstly, the pivotal quantity for 95% confidence interval for the proportion of the people in the population is given by;

      P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion = 0.345

           n = sample of participants = 1219 + 2313 = 3532

           p = population proportion

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population​ proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                         significance are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u>= [\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

    = [ 0.345-1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } } , 0.345+1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } } ]

    = [0.3293 , 0.3607]

Hence, 95% confidence interval for the proportion of people in the population being treated for hypertension is [0.3293 , 0.3607].

6 0
3 years ago
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