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lisabon 2012 [21]
3 years ago
12

noreen made 8 2/3 cups of snack mix for a party. her guest ate 3/4 of the mix. how much snack mix did her guest eat?

Mathematics
2 answers:
madreJ [45]3 years ago
5 0

Answer:

6\frac{1}{2}\text{ cups}

Step-by-step explanation:

Given,

Total snake mix for the party = 8\frac{2}{3} cups = \frac{26}{3} cups,

Also, the part of total mix eaten by the guest = \frac{3}{4}

Thus, the total mix eaten by them = part of mix eaten by them × total mix

= \frac{3}{4}\times \frac{26}{3}

=\frac{26}{4}

=6\frac{2}{4}

=6\frac{1}{2}\text{ cups}

miskamm [114]3 years ago
3 0
Noreen made 8 and 2/3 cups which after solving becomes 8.666
now the guest ate 3/4 which means 3/4 of 8.66 which is 6.50 which means the guest ate 6 1/2 cups
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Step-by-step explanation:

Data given and notation

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\sigma=0.4 represent the population deviation for the sample

n=50 sample size  

\mu_o =3.3 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is higher than 3.3, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3.3  

Alternative hypothesis:\mu > 3.3  

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We can replace in formula (1) the info given like this:  

z=\frac{3.4-3.3}{\frac{0.4}{\sqrt{50}}}=1.768  

P value

Since is a one right tailed test the p value would be:  

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