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iVinArrow [24]
3 years ago
11

Which ordered pair is a solution of the inequality? 2y + 6 < 8x

Mathematics
1 answer:
BigorU [14]3 years ago
7 0
<span>2x-5y=-6
8x+3y=68

|x y +1|
|2 -5 6| = 0
|8 3 -68|

DET = 6+40 = 46

x*DET = 340-18
x = 7

-y*DET = -136-48
y = 4 </span>
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x+9=18-2x
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3x+9=18
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4 0
3 years ago
PLEASE PLEASE PLEASE HELP ME
lubasha [3.4K]

Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD:

∵ m∠KDE = m∠KCD

∵ m∠DKE = m∠CKD

∵ DK is a common side

∴ Δ KDE is similar to ΔKCD

∴ \frac{KD}{KC}=\frac{DE}{CD}=\frac{KE}{KD}

∵ DE : CD = 5 : 3

∴ \frac{KD}{KC}=\frac{5}{3}

∴ KD = 5/3 KC

∵ KE = KC + 8

∵ \frac{KE}{KD}=\frac{5}{3}

∴ \frac{KC+8}{\frac{5}{3}KC }=\frac{5}{3}

∴ KC + 8 = \frac{25}{9}KC

∴ \frac{25}{9}KC - KC=8

∴ \frac{16}{9}KC=8

∴ KC = (8 × 9) ÷ 16 = 4.5

∴ KE = 8 + 4.5 = 12.5

∴ CE = 12.5 + 4.5 = 17

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3 years ago
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Step-by-step explanation:

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Answer:

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Y = -12 , -9

That’s the answer and good luck!
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