Which ordered pair is a solution of the inequality? 2y + 6 < 8x

1 answer:

7 0

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The odd- and even - number hotel rooms are on different sides of the hall. Room 231 is between witch two rooms

mario62 [17]

The first odd number before 231 which would be on the same side of the hall is 229. The first odd number after would be 233.
On the odd side of the hall, the order would be room 229, room 231, room 233.

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3 years ago

Value? Hint: Rationalize the denominator and<br><br> 4/4 - sqr6x

Diano4ka-milaya [45]

Answer:

The Answer is A

Step-by-step explanation:

I'm 100% right.

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2 years ago

Simplify 4(2n -1) – 6n

larisa86 [58]

Answer:

2n - 4

Step-by-step explanation:

expand brackets

8n - 4 - 6n

collect like terms

2n - 4

4 0

3 years ago

Read 2 more answers

What is the difference in simplest form? <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bn%5E2%2B3n%2B2%7D%7Bn%5E2%2B6n%2B8%7D-%5

Paha777 [63]

$\bf \cfrac{n^2+3n+2}{n^2+6n+8}-\cfrac{2n}{n+4}\implies \cfrac{n^2+3n+21}{(n+4)(n+2)}-\cfrac{2n}{n+4}
\\\\\\
\textit{so our LCD will just be (n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~(n+2)(2n)}{(n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~(2n^2+4n)}{(n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~2n^2-4n}{(n+4)(n+2)}
\implies 
\cfrac{-n^2-n+2}{(n+4)(n+2)}
\\\\\\
\cfrac{-(n^2+n-2)}{(n+4)(n+2)}\implies \cfrac{-\underline{(n+2)}(n-1)}{(n+4)\underline{(n+2)}}\implies \cfrac{-(n-1)}{n+4}\implies \cfrac{1+n}{n+4}$

3 0

3 years ago

You have prizes to ren

Agata [3.3K]

Answer:

$475.00

Step-by-step explanation:

Subtract $822.00 and $347.00 then you'll get $475.00

7 0

3 years ago