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lbvjy [14]
3 years ago
8

What is 24% of 1350 I will give 75 points

Mathematics
2 answers:
nika2105 [10]3 years ago
8 0
<h3>Answer:</h3><h2>324.</h2><h3>Step-by-step explanation:</h3>

To find 24% of 1,350, you must multiply 24% by 1,350.

To do this problem, we must turn the numbers to fractions.

Twenty-Four hundredths, 24 / 100 is your fraction for 24%.

Put 1,350 over 1 since 1,350 is a whole number.

So:

24 / 100 x 1,350 / 1.

1350 x 24 = 32400, 100 x 1 = 100.

Your answer is 32,400 / 100.

Get rid of the 2 zeroes in 400 and 100.

It should be 324 / 1.

Since 1 is just the number 1, the answer is 324.

If you have any questions, feel free to comment below.

Merry Christmas!

Andrew [12]3 years ago
8 0

Answer:

324.

Step-by-step explanation:

To find 24% of 1,350, you must multiply 24% by 1,350.

To do this problem, we must turn the numbers to fractions.

Twenty-Four hundredths, 24 / 100 is your fraction for 24%.

Put 1,350 over 1 since 1,350 is a whole number.

So:

24 / 100 x 1,350 / 1.

1350 x 24 = 32400, 100 x 1 = 100.

Your answer is 32,400 / 100.

Get rid of the 2 zeroes in 400 and 100.

It should be 324 / 1.

Since 1 is just the number 1, the answer is 324.

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What is an interval scale and what is it used for?
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3 years ago
Read 2 more answers
-5x-y= 8<br> -4x+y=2 solve the system
yan [13]

\huge\fcolorbox{blue}{aqua}{Answer:}

═════════════════════

1.- 5x - y = 8

<h3>Solve for x</h3>

-5x-y=8

-5x=8+y

-5x=y+8

\frac{-5x}{-5}=\frac{y+8}{-5}

x=\frac{y+8}{-5}

x=\frac{-y-8}{5}

<h3>Solve for y</h3>

-5x-y=8

-y=8+5x

-y=5x+8

\frac{-y}{-1}=\frac{5x+8}{-1}

y=\frac{5x+8}{-1}

y=-5x-8

────────────────────

2.-4x-y=2

<h3>Solve for x</h3>

-4x-y=2

-4x=2+y

-4x=y+2

\frac{-4x}{-4}=\frac{y+2}{-4}

x=\frac{y+2}{-4}

x=-\frac{y}{4}-\frac{1}{2}

<h3>Solve for y</h3>

-4x-y=2

-y=2+4x

-y=4x+2

\frac{-y}{-1}=\frac{4x+2}{-1}

y=\frac{4x+2}{-1}

y=-4x-2

════════════════════

Explanation:

#Carry on learning

7 0
2 years ago
What is the volume of the rectangular prism above? A.1/12<br> B.1/15<br> C.1/5<br> D.1/20
san4es73 [151]
<span>In the figure, all the dimensions of the cuboid
a = 4/5m side of the base
b = 1/3m second side of the base
c = h = 1/4m height solid
 
The volume is the product of the edge
V = abc = 4/5m * 1/3m * 1/4m = 4/60m</span>³ = 1/15m³

Answer B
3 0
3 years ago
At a farm, the average number of chickens, ducks, rabbits and sheep is 315 per type of animal. The average number of chickens, d
Greeley [361]

The average number of chickens, ducks, rabbits and sheep = 315 per type of animal.

The average number of chickens, ducks and rabbits = 320 per type of animal.

The number of sheep is 60 more than the number of rabbits.

Let us assume number of rabbits = x.

Number of sheep is 60 more than number of rabbits, that is = x+60.

There are half as many ducks as there are rabbits.

Therefore, number of ducks = x/2.

Let us assume number of chickens = y.

Adding  number of chickens, number of rabbits, number of sheep and number of ducks and dividing by 4 (because those are four types of animal).

\frac{y+x+x+60+x/2}{4}  = 315

Multiplying both sides by 4, we get

y+x+x+60+x/2 = 1260

Subtracting 60 from both sides

y+x+x+60-60+x/2 = 1260-60

y+x+x+x/2 = 1200.

Combining like terms .

y + 5x/2 = 1200

Multiplying both sides by 2, we get

<em>2y +5x = 2400  ------------equation (1)</em>

Adding  number of chickens, number of rabbits and number of ducks and dividing by 3 (because those are three types of animal).

\frac{y+x+60+x/2}{3}  = 320

Multiplying both sides by 3, we get

y+x+60+x/2 = 960

Subtracting 60 from both sides

y+ x+x/2 = 900

Combining like terms .

y+ 3x/2 = 900

Multiplying both sides by 2, we get

<em>2y+3x = 1800 --------------------equation (2)</em>

Multiplying first equation by 3 and second equation by -5, we get

(2y +5x = 2400 ) * 3   => 6y +15x = 7200

(2y+3x = 1800) *-5      =>

Adding

6y +15x = 7200

-10x + -15x = -9000.

_________________

-4y = -1800.

Dividing both sides by -4, we get

y=450.

<h3>Therefore, number of chickens are  450 there at the farm.</h3>


7 0
3 years ago
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