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3 years ago

A rectangular ice rink measures 25 m by 64 m. What are the dimensions of a square with the same area? PLZ HELP!

Mathematics

2 answers:

Anarel [89]3 years ago

8 0

40 m by 40 m

25 x 64 = 1600
40 x 40 = 1600

Slav-nsk [51]3 years ago

7 0

25x64=1600. a square would be 40x40=1600

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An angle measures 156° less than the measure of its supplementary angle. What is the measure of each angle?

GrogVix [38]

Answer:

12° and 168°

Step-by-step explanation:

If x is the angle, and y is the supplementary angle, then:

x + y = 180

x = y − 156

Solve the system of equations using substitution:

y − 156 + y = 180

2y = 336

y = 168

Plug back into either equation to find x:

x = 12

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4 years ago

What is the area of a garden that measures 4mx4mx6mx4mx10mx8m

topjm [15]

The area of the garden is 120 square metre

<h2>Explanation:</h2>

The picture of the garden is shown below. In this problem, we have:

One square
Two rectangles

Recall that the area of a square is given by:

$A_{s}=L^2 \\ \\ A_{s}:Area \ of \ a \ square \\ L:Side \ of \ the \ square$

On the other hand, the area of a rectangle is given by:

$A_{r}=L_{1}\times L_{2} \\ \\ \\ A_{r}:Area \ of \ a \ rectangle \\ \\ L_{1}:Side \ 1 \ of \ the \ rectangle \\ \\ L_{2}:Side \ 2 \ of \ the \ rectangle$

Therefore:

FOR THE SQUARE:

$L=4m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{s}=4^2 \\ \\ \boxed{A_{s}=16m^2}$

FOR THE RECTANGLE 1:

$L_{1}=6m \\ L_{2}=4m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{r_{1}}=6(4) \\ \\ \boxed{A_{r_{1}}=24m^2}$

FOR THE RECTANGLE 2:

$L_{1}=10m \\ L_{2}=8m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{r_{2}}=10(8) \\ \\ \boxed{A_{r_{2}}=80m^2}$

Finally, the area of a garden is the sum of the three areas:

$A_{total}=A_{s}+A_{r_{1}}+A_{r_{2}} \\ \\ A_{total}=16m^2+24m^2+80m^2 \\ \\ A_{total}=16+24+80 \\ \\ \boxed{A_{total}=120m^2}$

<h2>Learn more:</h2>

Area of a pizza: brainly.com/question/12878495

#LearnWithBrainly

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3 years ago

What is the distance between 5,4 and -1,1

spayn [35]

Answer:

3 $\sqrt{5}$

Step-by-step explanation:

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (5, 4) and (x₂, y₂ ) = (- 1, 1)

d = $\sqrt{(-1-5)^2+(1-4)^2}$

= $\sqrt{(-6)^2+(-3)^2}$

= $\sqrt{36+9}$

= $\sqrt{45}$

= 3 $\sqrt{5}$ ← exact value

≈ 6.71 ( to 2 dec. places )

8 0

3 years ago