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Vera_Pavlovna [14]
3 years ago
5

The density of a certain material is such that it weighs 6 pounds per pint of volume.

Mathematics
1 answer:
ella [17]3 years ago
3 0

Answer:

Density = 5751.66 gram per litre

Step-by-step explanation:

It is given that the density of a certain material 6 pounds per pint.

The conversion from pint to liter is as follows :

1 pint = 0.473 litre

The conversion from pounds to kg is as follows :

1 pound = 453.59 kg

We need to express the density from pounds per pint to grams per liter.

1 pound per pint = 958.611 gram per litre

So,

6 pound per pint = 958.611 × 6 gram per litre

6 pound per pint  = 5751.66 gram per litre

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Mrrafil [7]

Answer :

Factors of 12 are

1  \times 12 \\ 2  \times  6 \\ 3  \times  4.

  1. 5 multiplied by any number can never give 12 . Multiples of 5 are
  2. 5 \: 10 \: 15 \: 20
  3. 7 multiples are
  4. 7 \: 14 \: 21
  5. Same applies for all the listed numbers
6 0
3 years ago
How many degrees is 7/4 of a semicircle?
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Answer:

315

Step-by-step explanation:

7/4 of 180°

= 1.75 * 180

= 315°

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40
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It's simple, you just have to do this:

L=\int\limits_{a}^{b}\sqrt{\left(\frac{dx}{dt}\right)^2+\left(\frac{dy}{dt}\right)^2}~dt

x=3t-t^3

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replacing

L=\int\limits_{0}^{\sqrt{3}}\sqrt{\left(3-3t^2\right)^2+\left(6t\right)^2}~dt

L=\int\limits_{0}^{\sqrt{3}}\sqrt{9-18t^2+9t^4+36t^2}~dt

L=\int\limits_{0}^{\sqrt{3}}\sqrt{9+9t^4+18t^2}~dt

L=\int\limits_{0}^{\sqrt{3}}\sqrt{(3t^2+3)^2}~dt

L=\int\limits_{0}^{\sqrt{3}}(3t^2+3)~dt

L=t^3+3t|_0^{\sqrt{3}}

\boxed{\boxed{L=3\sqrt{3}+3\sqrt{3}=6\sqrt{3}}}
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