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3 years ago

The range of the function f(x) = x + 5 is {7, 9}. What is the function’s domain?

Mathematics

1 answer:

Delicious77 [7]3 years ago

8 0

Answer:

Step-by-step explanation:

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Check the consistency of 2x-3y=7 and x-2y+1=0

Furkat [3]

Answer:

x = 17, y = 9

or as an ordered pair, (17, 9).

The equations are consistent.

Step-by-step explanation:

2x - 3y = 7

x - 2y = -1 Multiply this equation by -2:

-2x + 4y = 2 Add this to the first equation:

y = 9.

Plug y = 9 into the second equation:

x - 2*9 = -1

x = -1 + 18 = 17.

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2 years ago

What do you do when you have two exponent in the same parentheses adding to each other

morpeh [17]

Answer:

Raise the power

Step-by-step explanation:

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3 years ago

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Answer this question pls!! (Will give Brainliest)

AnnyKZ [126]

Answer:

D. y = 12.5x + 15

Step-by-step explanation:

Using the values provided in the table, the only equation that would be valid would be the following...

y = 12.5x + 15

That is because if we substitute any value provided in the table for x , this equation will correctly output the y value shown in the table for the attached x-value. For example, in the table 5 nights (x = 5) should have a total cost of 77.5 (y = 77.5)... Therefore, if we substitute 5 for x in the function it should give us 77.5 which it does.

y = 12.5(5) + 15

y = 62.5 + 15

y = 77.5

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3 years ago

Pls give an explanation w your answer

Shalnov [3]

$a^{\frac{1}{n}}=\sqrt[n]{a}\\\\\left(a^n\right)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}$
therefore
$64^\frac{1}{4}=\left(2^6\right)^\frac{1}{4}=2^{6\cdot\frac{1}{4}}\\\\=2^\frac{6}{4}=2^{1\frac{2}{4}}=2^{1+\frac{2}{4}}=2\cdot2^\frac{2}{4}\\\\=2\sqrt[4]{2^2}=2\sqrt[4]4$
Other method:
$64^\frac{1}{4}=\sqrt[4]{64}=\sqrt[4]{16\cdot4}=\sqrt[4]{16}\cdot\sqrt[4]4=2\sqrt[4]4$

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2 years ago

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What is the measure of angle VYZ

irakobra [83]

Answer:

$\boxed{\sf C. \ 161 ^{ \circ}}$

Step-by-step explanation:

<em>Opposite angles are also congruent angles, meaning they are equal or have the same measurement.</em>

$\sf \implies \angle VYZ = \angle WYT \\ \\ \sf \implies(8x + 1) ^{ \circ} = (9x - 19)^{ \circ} \\ \\ \sf \implies 8x^{ \circ} + 1^{ \circ} = 9x^{ \circ} - 19^{ \circ} \\ \\ \sf \implies 8x^{ \circ} - 9x^{ \circ} + 1^{ \circ} = - 19^{ \circ} \\ \\ \sf \implies - x^{ \circ} = - 19^{ \circ} - 1^{ \circ} \\ \\ \sf \implies \cancel{ -} x^{ \circ} = \cancel{- }20^{ \circ} \\ \\ \sf \implies x^{ \circ} = 20^{ \circ}$

$\therefore$

$\sf \implies \angle VYZ =(8x + 1) ^{ \circ} \\ \\ \sf \implies \angle VYZ =(8 \times 20 + 1) ^{ \circ} \\ \\ \sf \implies \angle VYZ =( 160+ 1) ^{ \circ} \\ \\ \sf \implies \angle VYZ =161 ^{ \circ}$

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3 years ago