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kolezko [41]
3 years ago
14

The superintendent of a school district wanted to predict the percentage of students passing a sixth-grade proficiency test. she

obtained the data on percentage of students passing the proficiency test (% passing), mean teacher salary in thousands of dollars (salaries), and instructional spending per pupil in thousands of dollars (spending) of 47 schools in the state. following is the multiple regression output with y = % passing as the dependent variable, x1 = salaries and x2 = spending: which of the following is the correct null hypothesis to determine whether there is a significant relationship between percentage of students passing the proficiency test and the entire set of explanatory variables?
a) h1: =b3=0

b) h1: =b1=0

c) h1: =b2=0

d) h1: =b0=0
Mathematics
1 answer:
Orlov [11]3 years ago
7 0

Answer:

B. H1= b1=0

Step-by-step explanation:

the alternative hypothesis is correct

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The probability is 0.9671.

The z-score for this is given by

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elena-s [515]
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A parabola can be drawn given a focus of (5, -3) and a directrix of y=1. Write the equation of the parabola in any form.
Anna71 [15]

Answer:

(x²-10x+33)/(-8) = y

Step-by-step explanation:

The distance between any point on a parabola from both its focus and directrix are the same.

Let's say we have a point (x,y) on the parabola. We can then say that using the distance formula,

\sqrt{(x-5)^2+(y-(-3))^2}is the distance between (x,y) and the focus. Similarly, the distance between (x,y) and the directrix is |y-1| (I use absolute value here because distance is always positive). We can find this equation by taking the shortest distance from the point to the line. Because the closest point to the line will be the same x value as the point itself, the distance is simply the distance between the y value of the point and the y value of the directrix.

Equating the two equations given, we have

\sqrt{(x-5)^2+(y-(-3))^2} = |y-1|

square both sides to get

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expand the y components

(x-5)² + y²+6y+9 = y²-2y+1

subtract y²+6y+9 from both sides

(x-5)² = -8y - 8

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x²-10x+25 = -8y - 8

add 8 to both sides to isolate the -8y

x²-10x+33 = -8y

divide both sides by -8 to isolate y

(x²-10x+33)/(-8) = y

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3 years ago
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