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damaskus [11]
3 years ago
12

Evaluating a function graphically? How do I solve this

Mathematics
1 answer:
Artyom0805 [142]3 years ago
6 0
Answer:

f(1) = -6

Explanation:

When you look at the points with x = 1, you will see a point that is open (o) and closed (•) The point that is closed (the one you are looking for) is an actual point of the function. The open point is where the function is discontinuous.
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Select the correct answer.<br> Solve
Molodets [167]

Answer:

B 1 1/7

Step-by-step explanation:

- 9 2/7 - ( -10 3/7)

We know subtracting a negative is like adding

- 9 2/7 +10 3/7

10 3/7 - 9 2/7

Putting this vertical

10  3/7

-9  2/7

-----------------

1   1/7

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2 years ago
Line segment SU is dilated to create S'U' using the dilation rule DQ,2.5.
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6 units on edg 2020

Step-by-step explanation:

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3 years ago
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How do you solve this problem
lora16 [44]
X² = 17

To simplify this, you need to find the square root of x², which is x, and the square root of 17.

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3 years ago
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A dance studio is purchasing tutus for an annual performance. The table represents the number of tutus available for different p
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30$ C

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The following six independent length measurements were made (in feet) for a line: 736.352, 736.363, 736.375, 736.324, 736.358, a
horrorfan [7]

Answer:

Assuming population data

\sigma = \sqrt{0.000354}=0.0188

Assuming sample data

s = \sqrt{0.000425}=0.0206

Step-by-step explanation:

For this case we have the following data given:

736.352, 736.363, 736.375, 736.324, 736.358, and 736.383.

The first step in order to calculate the standard deviation is calculate the mean.

Assuming population data

\mu = \frac{\sum_{i=1}^6 X_i}{6}

The value for the mean would be:

\mu = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359

And the population variance would be given by:

\sigma^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6}

And we got \sigma^2 =0.000354

And the deviation would be just the square root of the variance:

\sigma = \sqrt{0.000354}=0.0188

Assuming sample data

\bar X = \frac{\sum_{i=1}^6 X_i}{6}

The value for the mean would be:

\bar X = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359

And the population variance would be given by:

s^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6-1}

And we got s^2 =0.000425

And the deviation would be just the square root of the variance:

s = \sqrt{0.000425}=0.0206

6 0
3 years ago
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