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3 years ago

A Prefeitura da Cidade Feliz doou um

Mathematics

1 answer:

Igoryamba3 years ago

8 0

Aqui temos a seguinte divisao de terreno:

creche + banheiros + academia = 45% + 3% + 12% = 60%

O que sobra: Fazendo a conta, 100 - 60 = 40, restará 40%

No enunciado informa que sobraram 960m².

Logo concluimos que 40% = 960m²

Sendo assim, regra de 3:

m² %

960 -------- 40

X -------- 60

40X = 960 . 60

X = 57600/40

X = 1440

Logo 1440m² é destinado para: creche, banheiros públicos e academia

de ginástica comunitária.

O terreno tem um total de 1440 + 960 = 2400m²

para cada espaço - novamente diversas regra de 3:

→ creche = 45%

m² %

2400 -------- 100

X -------- 45

X = 108000/100 = 1080

→ banheiros públicos = 3%

m² %

2400 -------- 100

X -------- 3

X = 7200/100 = 72

→ academia de ginástica comunitária = 12%

m² %

2400 -------- 100

X -------- 12

X = 28800/100 = 288

provando:

60% = 1440m² (visto acima)

creche - 1080

banheiros - 72

academia - 288

1080 + 72 + 288 = 1440 (60%)

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alina1380 [7]

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3 years ago

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