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Serhud [2]
3 years ago
15

Suppose that E and F are two events and that Upper P (Upper E and Upper F )equals0.3 and Upper P (Upper E )equals0.5. What is Up

per P (F|E )​? Upper P (F|E )equals nothing ​(Type an integer or a​ decimal.)
Mathematics
1 answer:
m_a_m_a [10]3 years ago
6 0

Answer:

P(\frac{F}{E}) =\frac{0.3}{0.5} =0.6

Step-by-step explanation:

<u>Step 1</u>:-

Suppose that E and F are two events and that P(E n F) = 0.3

also given P(E) =0.5

<u>Conditional probability</u>:-

if E₁ and E₂ are two events in a Sample S and P(E₁)≠ 0, then the probability of E₂ , after the event E₁ has occurred, is called the <u>Conditional probability</u>

of the event E₂ given  E₁ and is denoted by

P(\frac{F}{E}) = \frac{P(EnF)}{P(E)}

P(\frac{F}{E}) =\frac{0.3}{0.5} =0.6

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What is the order of operations to solve this problem?<br> 10 x 5 + 2 / 2 = 60
Slav-nsk [51]

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E = Exponents

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A videotape store has an average weekly gross of $1,158 with a standard deviation of $120. Let x be the store's gross during a r
statuscvo [17]

Answer:

The number of standard deviations from $1,158 to $1,360 is 1.68.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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\mu = 1158, \sigma = 120

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Z = \frac{1360 - 1158}{120}

Z = 1.68

The number of standard deviations from $1,158 to $1,360 is 1.68.

3 0
3 years ago
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