Answer:
a!!
Step-by-step explanation:
Let the height of the building be x. Let the initial distance of the ant from the building be y, then
tan 32 = x/y
y = x/tan 32 . . . . . . . . (1)
tan 22 = x/(y + 66)
y tan 22 + 66 tan 22 = x
y = (x - 66 tan 22)/tan 22 . . . . . . . . (2)
Equating (1) and (2), we have
x/tan 32 = (x - 66 tan 22)/tan 22
x tan 22 = x tan 32 - 66 tan 22 (tan 32)
x(tan 32 - tan 22) = 66 tan 22 (tan 32)
x = (66 tan 22 (tan 32))/(tan 32 - tan 22) = 66(0.4040)(0.6249)/(0.6249 - 0.4040) = 16.6626/0.2208 = 75.4
Therefore, the height of the building is 75.4 feet.
Step-by-step explanation:
Below is an attachment containing the solution.
Answer:
Option (2).
Step-by-step explanation:
In the figure attached,
A, C and B are the points lying on a straight line.
2 lines EC and DC have been drawn by extending the lines from C to E and D respectively.
Ray CE is the angle bisector of ∠ACD.
That means CE divides ∠ACD in two equal parts.
m∠ACE = m∠DCE
Since m∠ACD = m∠ACE + m∠DCE
= 2(m∠ACE)
m∠ACE = 
Therefore, option (2) will be the answer.
I think answer should be d. Please give me brainlest let me know if it’s correct or not okay thanks bye