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2 years ago

6. Does the set of ordered

1 answer:

6 0

Answer: this is not a function because the X values are repeating for example we see that 0 is set in the X value side it can’t have 5 and -5 as it’s y at the same time therefor it’s not a function

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The population of Corpus Christi Texas is 305,215 the population of Laredo Texas is 236,091 how many more people live in Corpus

Naddik [55]

Answer:

69,124

Step-by-step explanation:

subtract 305,215 by 236,091

305,215

- 236,091

5 0

3 years ago

7. If every short side is 1.5 inches and every long side is 3 inches, what is the perimeter?

hjlf

The answer 2 your question is 24in

6 0

3 years ago

Read 2 more answers

(X+2y)(x-2y) how do I solve this

Fudgin [204]

Step-by-step explanation:

(x+2y)(x-2y)

x^2-2xy+2xy-(2y)^2
x^2-4y^2

5 0

3 years ago

Ben has a cell phone plan that provides 200 free minutes each month for a flat rate of $39. For any minutes over 200, Ben is cha

faltersainse [42]

Answer:

$\left\{\begin{matrix}39 & x\leq 200\\ 39+(x-200)\times 0.35 & x>200\end{matrix}\right.$

Step-by-step explanation:

We are given that Ben has a cell phone plan that provides 200 free minutes each month for a flat rate of $39.

We are also told that For any minutes over 200, Ben is charged $0.35 per minute.

let x be the minutes used each month

So, if $x\leq 200$

So, coat will be $39

If $x>200$

So, Ben is charged $0.35 per minute

So, when $x>200$

So, charge = $39+(x-200)\times 0.35$

So, the piecewise functions accurately represents charges based on Ben's cell phone :

$\left\{\begin{matrix}39 & x\leq 200\\ 39+(x-200)\times 0.35 & x>200\end{matrix}\right.$

4 0

3 years ago

Read 2 more answers

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$

3 0

3 years ago

Read 2 more answers