All categories

2 years ago

6. Does the set of ordered

1 answer:

6 0

Answer: this is not a function because the X values are repeating for example we see that 0 is set in the X value side it can’t have 5 and -5 as it’s y at the same time therefor it’s not a function

You might be interested in

What is the circumference of a circle with a diameter of 9 cm?

Kamila [148]

Answer:

the answer=28.27cm

using formula

c=2πr

d=2r

solving for c

C=πd

=π.9

=28.27

hope it help you

5 0

2 years ago

How do I make 3 - 10= 7 into an integer

Delicious77 [7]

All you have to do is subtract 10 from 3, which equals -7, and there you have an integer

8 0

3 years ago

Given one factor of the polynomial, factor the polynomial completely.

astraxan [27]

Answer:

The factors are (x - 1)(x - 5)(x + 2).

Step-by-step explanation:

Long division:

x - 5 )x^3 - 4x^2 - 7x + 10( x^2 + x - 2 <--------- Quotient.

x^3 - 5x^2

x^2 - 7x

x^2 - 5x

- 2x + 10

-2x + 10

...........

x^ 2 + x - 2 = (x + 2)(x - 1).

7 0

3 years ago

For any circle, which ratio is equal to the number n? Select all that apply. Plsss help me!!

barxatty [35]

Answer:

Options A-C-F

Step-by-step explanation:

we know that

The circumference of a circle is equal to

$C=\pi D$ or $C=2\pi r$

where

D is the diameter and r is the radius

therefore

$\pi =\frac{C}{D}$ or $\pi =\frac{C}{2r}$

The number pi is the ratio circumference - diameter or is the ratio circumference - 2 times radius

The area of the circle is equal to

$A=\pi r^{2}$

therefore

The number pi is the ratio Area - radius squared

6 0

3 years ago

Primitive function for: 1. f(x)=4e2x+e−x, sådan att F(0)=2

Free_Kalibri [48]

The primitive function for $f(x) = 4e^{2x} + e^{-x}$ is given by it's indefinite integral.

To calculate it, recall:

$\frac{d}{dx}e^{ax}=ae^{ax}$

$\int c f(x)dx = c\int f(x)dx$

Let's begin

$\int 4e^{2x}+e^{-x}dx \\4\int e^{2x}dx+ \int e^{-x}dx\\4\frac{e^{2x}}{2}+\frac{e^{-x}}{-1} + c\\$

$F(x) = 2e^{2x}-e^{-x} +c$

To find the costant, we just need to use the fact that $F(0)=2$

$F(0) = 2 \\4e^{0}+e^{0} + c =2\\5+c =2\\c=-3$

Therefore,

$\boxed{F(x) = 2e^{2x} - e^{-x} -3 }$

6 0

2 years ago