For this case we have the following function:
f (t) = -16t2 + 32t + 384
By definition we have to:
The average rate of change:
AVR = (f (t2) - f (t1)) / (t2 - t1)
Where,
For t1 = 4
f (4) = -16 * (4) ^ 2 + 32 * (4) + 384
f (4) = 256
For t2 = 6
f (6) = -16 * (6) ^ 2 + 32 * (6) + 384
f (6) = 0
Substituting values we have:
AVR = (0 - 256) / (6 - 4)
AVR = -128
Answer:
The average rate of change of f (t) from t = 4 seconds to t = 6 seconds is -128 feet per second.
Answer:
67.5 ft
Step-by-step Explanation:
==>Given:
∆MAB and ∆MNP, such that:
AB is parallel to NP
MN and MP are transversal
MN = 71.5 ft
MP = 97.5 ft
AN = 22ft
MA = MP - AN = 71.5 - 22 = 49.5 ft
MB = x
==>Required:
Value of x
==>Solution:
From the figure given, since AB is parallel to NP, and MN and MP are transversal, thus:
<MAB is congruent to <MNP
<MBA is congruent to <MPN
This implies that ∆MAB is similar to ∆MNP
Therefore, the ratio of their corresponding sides would be the same, and also proportional.
Thus,
MA/MN = MB/MP
49.5/71.5 = x/97.5
=>Cross multiply to solve for x
49.5 × 97.5 = x × 71.5
4,826.25 = 71.5x
=>Divide both sides by 71.5
4,826.25/71.5 = x
67.5 = x
x = 67.5 ft
Answer:
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