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3 years ago

What is the area of a triangle with b=146.2, c=209.3, and A=62.2°?

Mathematics

2 answers:

timama [110]3 years ago

8 0

Law of cosines. Let me know if you still need help.

Ratling [72]3 years ago

6 0

Answer:

D.) 13, 533.9

Step-by-step explanation:

You can use all the information in the equation of Area when you have side, angle, side. A = 1/2 bc sin A. Use a calculator and it will give you the solution.

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A circle has a circumference of 6cm. find the diameter of the circle

AleksAgata [21]

Answer:

1.9 or 2

Step-by-step explanation:

To find diameter you do,

d= C/pi

C is circumference

so, d=6/3.14

=1.910... or 2

Hope this helps :)

7 0

3 years ago

You and a friend are sharing a swing. You have swung 11 times while your friend has swung twice as many times. Which of the foll

strojnjashka [21]

Answer:

20.

Step-by-step explanation:

You swung 11 times, and your friend swung twice as many times as that.

11x2=22

22 rounded to the nearest ten is 20.

6 0

3 years ago

Read 2 more answers

Using the exponential function y=-()* fill in the table below.

xenn [34]

Y=4
Y=3
Y=2
Y=1
Y=0
Y=-1
Y=-2
Y=-3
Y=-4

8 0

3 years ago

Plz look at this and solve it plz

Ghella [55]

Answer:

Area= 452.16 cm2

Step-by-step explanation:

12 x 12 = 144

144 x 3.14 = 452.16

5 0

3 years ago

Solve each quadratic equation by completing the square. Give exact answers--no decimals.

denis-greek [22]

Answer:

$x_1 = \frac{3}{2} + \frac{1}{2}(\sqrt{47})i\\\\x_2 = \frac{3}{2} - \frac{1}{2}(\sqrt{47})i\\\\$

Step-by-step explanation:

In this problem we have the equation of the following quadratic equation and we want to solve it using the method of square completion:

$x ^ 2 -3x +14 = 0$

The steps are shown below:

For any equation of the form: $ax ^ 2 + bx + c = 0$

1. If the coefficient a is different from 1, then take a as a common factor.

In this case $a = 1$ .

Then we go directly to step 2

2. Take the coefficient b that accompanies the variable x. In this case the coefficient is -3. Then, divide by 2 and the result squared it.

We have:

$\frac{-3}{2} = -\frac{3}{2}\\\\(-\frac{3}{2}) ^ 2 = (\frac{9}{4})$

3. Add the term obtained in the previous step on both sides of equality:

$x ^ 2 -3x + (\frac{9}{4}) = -14 + (\frac{9}{4})$

4. Factor the resulting expression, and you will get:

$(x -\frac{3}{2}) ^ 2 = -(\frac{47}{4})$

Now solve the equation:

Note that the term $(x -\frac{3}{2}) ^ 2$ is always > 0 therefore it can not be equal to $-(\frac{47}{4})$

The equation has no solution in real numbers.

In the same way we can find the complex roots:

$(x -\frac{3}{2}) ^ 2 = -(\frac{47}{4})\\\\x -\frac{3}{2} = \±\sqrt{-(\frac{47}{4})}\\\\x = \frac{3}{2} \±\frac{1}{2}\sqrt{-47}\\\\x = \frac{3}{2} \±\frac{1}{2}(\sqrt{47})i\\\\x_1 = \frac{3}{2} + \frac{1}{2}(\sqrt{47})i\\\\x_2 = \frac{3}{2} - \frac{1}{2}(\sqrt{47})i\\\\$

7 0

3 years ago

Read 2 more answers