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Rudiy27
3 years ago
9

Factor by grouping 3x^2-11x+10

Mathematics
1 answer:
Burka [1]3 years ago
7 0

Answer: (x - 2)(3x - 5)

Step-by-step explanation:

I'm using the berry method to factor, so first, I multiply 3 times 10 to get 30. Now I have to figure out what two numbers, when multiplied together, yield 30 and when are added together, give me -11. Those two numbers are -6 and -5. The equation now becomes (3x -6)(3x -5). Reducing the first binomial: (3x - 6)/3 = (x - 2)

the solution is (x - 2)(3x - 5), and we can check this by multiplying it out, which gives us our starting number, meaning it's correct.

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When two values are given for a linear function, it is easier to obtain the equation using the two-point form, namely
(y-y1)=m(x-x1)  where
m=slope=(y2-y1)/(x2-x1)
and
(x1,y1) and (x2,y2) are the given two points.

Here
(x1,y1)=(25,0.99), and
(x2,y2)=(100,3.99)
Find slope, m=(y2-y1)/(x2-x1)=(3.99-0.99)/(100-25)=3/75=0.04
Find equation:
(y-y1)=m(x-x1) 
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3 years ago
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Answer:

Step-by-step explanation:

5 0
2 years ago
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 nigh
lorasvet [3.4K]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean GPA of night students and μ2 be the mean GPA of day students.

The random variable is μ1 - μ2 = difference in the mean GPA of night students and the mean GPA of day students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 ≠ μ2 H1 : μ1 - μ2 ≠ 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 2.35

x2 = 2.58

s1 = 0.46

s2 = 0.47

n1 = 30

n2 = 25

t = (2.35 - 2.58)/√(0.46²/30 + 0.47²/25)

t = - 1.82

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.46²/30 + 0.47²/25]²/[(1/30 - 1)(0.46²/30)² + (1/25 - 1)(0.47²/25)²] = 0.00025247091/0.00000496862

df = 51

We would determine the probability value from the t test calculator. It becomes

p value = 0.075

Alpha = 5% = 0.05

Since alpha, 0.05 < than the p value, 0.075, then we would fail to reject the null hypothesis.

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Answer:

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