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Dmitry [639]
3 years ago
8

Which of the following is a step used in the construction of an equilateral triangle inscribed in a circle?

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
3 0
It would be better with the image, I think it is the 3 one
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The product of four numbers is 540. Three of the four numbers are 2, 5 and 9. What is the other number?
Whitepunk [10]

Step-by-step explanation:

2*5*9*x = 540

x = 540/90 = 54/9 = 6

option D

8 0
1 year ago
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Find the perimeter of ABC with vertices A (1,-6), B (1,-3),<br> and C (-4,-6).
Crazy boy [7]

Answer:

p = 8 +  \sqrt{34}  = 13.83095...

Step-by-step explanation:

we can easily calculate the perimeter of three points, using vectors. See the picture...

5 0
2 years ago
What are the missing angles? What is the relationship between the measures of supplementary angles?
goldenfox [79]

Answer:

6=100°

8=80°

7=100°

9=80°

Step-by-step explanation:

If 6 is 100°

in a straight line theres 180 degrees

180-100=80°

8 is 80°

opposite 6 to 7 there are parallel corresponding angles meaning the angle opposite it will be the same. 8 with 9.

same with

5 0
3 years ago
2
Zigmanuir [339]

Answer:

The weight of the water in the pool is approximately 60,000 lb·f

Step-by-step explanation:

The details of the swimming pool are;

The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet

The depth of the pool = 5 feet

The density of the water  in the pool = 60 pounds per cubic foot

From the question, we have;

The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g

The volume of water in the pool = Cross-sectional area × Depth

∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³

Acceleration due to gravity, g ≈ 32.09 ft./s²

∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N

266,196.089 N ≈ 60,000 lb·f

The weight of the water in the pool ≈ 60,000 lb·f

6 0
2 years ago
(2b) A rectangular prism measures 2 &amp; 2/5 inches by 3 &amp; 1/5 inches by 2 inches. How many cubes with edge length 1/5 inch
erastova [34]

Answer:

1920 cubes.

Step-by-step explanation

Turn both the mix numbers into improper fractions.

2 2/5 = 12/5

3 1/5 = 16/5

Then you will turn 1/5 into its reciprocal and multiply both the improper fractions by it. You can just casually multiply 2 and 5.

12/5 * 5/1 = 12

16/5 * 5/1 = 16

2 * 5 = 10

Next you multiply all together to get 1920 cubes.

(I could be missing a step. I apologize if I did.)

3 0
3 years ago
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