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OLEGan [10]
3 years ago
9

The Woodson and Baker families went to the Burger Shack for dinner. The Woodsons bought 3 burger meals and 4 hot dog meals for $

48. The Bakers bought 6 burger meals and 2 hot dog meals for $60. How much does each meal cost? Show your work using systems of equations
Mathematics
1 answer:
tatiyna3 years ago
5 0

Answer:

Burger meal costs $8 and hot dog meal costs $6.

Step-by-step explanation:

To find the price per meal, write a system of equations.

Let b = cost of a burger meal and d = cost of a hot dog meal.

Write the equation 3b + 4d = 48 for the Woodsons.

Write the equation 6b + 2d = 60 for the Barkers.

Use elimination to solve the system. Begin by making the coefficients of one variable the same in both equations by multiplying 3b + 4d = 48 by 2.

2(3b + 4d = 48) ----> 6b + 8d = 96

Stack the equations and subtract.

   6b + 8d = 96

-   6b + 2d = 60

------------------------

            6d = 36

              d = 6

Substitute d = 6 into one equation to solve for b.

3b + 4(6) = 48

3b + 24 = 48

3b = 24

b = 8

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Largest value 5/9,2/3,11/8
Dima020 [189]
Answer: 11/8

11/8= 1 3/8

1 3/8 > 2/3
6 0
2 years ago
If the point (3,3) lies on the graph of y=f(x), what point lies on y=f(x-2)?
My name is Ann [436]

Answer:

  A.  (5, 3)

Step-by-step explanation:

Making use of the hint:

  x -2 = 3

  x = 5 . . . . . . add 2

The point (x, 3) is on the graph for x=3.

The point (x-2, 3) is on the graph for x=5, so ...

  the graph of (x, f(x-2)) will include the point (5, 3).

3 0
3 years ago
Read 2 more answers
Calcula y comprueba las ecuaciones: porfavor alguienn la nesesito pliss a) 2X = 6 b) 10 + Z = 20 c) P + 9 = 11 d) 3X + 8 = + 29
Alexeev081 [22]

Answer:

<u>a) x = 3</u>

<u>b) z = 10</u>

<u>c) p = 2</u>

<u>d) x = 7</u>

<u>e) u = 1</u>

Step-by-step explanation:

a) 2x = 6

Despejamos x dividiendo por 2 a amabos lados de la eacuacion.

(2/2)x = 6/2

<u>x = 3</u>

Si remplazamos x en la ecuación original:

2(3)=6

6 = 6

Queda demostrado.

b) 10 + z = 20

Despejamos z restando 10 en amabos lados de la eacuacion.

10-10+z = 20-10

<u>z = 10</u>

Si remplazamos z en la ecuación original:

10 + 10=20

20 = 20

Queda demostrado.

c) p + 9 = 11

Despejamos p restando 9 en amabos lados de la eacuacion.

p + 9 - 9 = 11-9

<u>p = 2</u>

Si remplazamos p en la ecuación original:

2 + 9 = 11

11 = 11

Queda demostrado.

d) 3x + 8 = 29

Despejamos x restando 8 en amabos lados de la eacuacion y luego divideindo por 3 en ambos lados de la ecuación.

3x+8-8 = 29-8

3x = 21

(3/3)x = 21/3

<u>x = 7</u>

Si remplazamos x en la ecuación original:

3(7) + 8 = 29

21 + 8 = 29

29 = 29

Queda demostrado

e) 2u + 8 = 10

Despejamos u restando 8 en amabos lados de la eacuacion y luego divideindo por 2 en ambos lados de la ecuación.

2u+8-8 = 10-8

2x = 2

(2/2)x = 2/2

<u>x = 1</u>

Si remplazamos x en la ecuación original:

2(1) + 8 = 10

2 + 8 = 10

10 = 10

Queda demostrado

Espero te haya sido de ayuda!

5 0
3 years ago
What is the binomial expansion of (x + 2y)7?
borishaifa [10]
<h2>Thus, the required "option 4)"  is correct.</h2>

Step-by-step explanation:

We find,

(x+2y)^7

To find, the binomial expansion of of (x+2y)^7 = ?

We know that,

(x+y)^{n} =^nC_0x^n+^nC_1x^{n-1}y+nC_2x^{n-2}y^2+nC_3x^{n-3}y^3+...+^nC_ny^n

∴ (x+2y)^7

Here, n = 7, x = x and y = 2y

(x+2y)^7= ^7C_0x^7+^7C_1x^{7-1}(2y)+^7C_2x^{7-2}(2y)^2+^7C_3x^{7-3}(2y)^3+^7C_4x^{7-4}(2y)^4+^7C_5x^{7-5}(2y)^5+^7C_6x(2y)^6+(2y)^7=x^7+7x^{6(2y)+21x^{5}4y^2+35x^{4}8y^3+^35x^{3}16y^4+21x^{2}32y^5+7x64y^6+128y^7

=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7

∴ The binomial expansion of of (x+2y)^7

=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7

Thus, the required "option 4)"  is correct.

7 0
3 years ago
Each bowling ball weighs 7.3*10^3 grams. The bowling alley has 2.0*10^2 bowling balls. How much do they all weigh, combined? Exp
Alexandra [31]

Answer:

1.46 x 10⁶g

Step-by-step explanation:

Given parameters:

Weight of each bowling ball  = 7.3 x 10³g

Number of balls in the bowling alley = 2.0 x 10²bowling balls

Unknown

The weight of the balls in the alley  = ?

Solution:

To find the weight of the balls in the alley, multiply the mass of each balls with the total number of balls;

 Weight of the balls = 7.3 x 10³ x 2.0 x 10²

 Weight of the balls  = (7.3 x 2.0) x 10³⁺²

 Weight of the balls  = 14.6 x 10⁵g

 Therefore, the weight of the balls  = 1.46 x 10⁶g

3 0
3 years ago
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