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TiliK225 [7]
4 years ago
5

I dont know how or what equation to write. Question#4

Mathematics
1 answer:
Tatiana [17]4 years ago
6 0

f(x)=3+.50X, You start out with three dollars and pay fifty cents every time you taste chili (x)

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Last year my family decided to put on a play It was A Great success . 200 people attended and we earned a total of 800 . If adul
nata0808 [166]

Answer:

200 adults

Step-by-step explanation:

We can set-up a system of equations to find the number of adults. We know children and adults attended. We will let c be the number of children and a be the number of adults. Since 200 people attended, then c+a=200.

We also know they made $800 and adult tickets cost $4 and child tickets cost $2. We can write 2c+4a=800.

We will solve by substituting one equation into the other. We start by solving the first equation for c. c+a=200 becomes c=200-a.

Now we substitute c=200-a into 2c+4a=800. Simplify and isolate the variable a.

  • 2(200-a)+4a=800
  • 400-2a+4a=800
  • 400+2a=800
  • 400-400+2a=800-400
  • 2a=400
  • a=200

This means that 200 adults attended and 0 children attended.

8 0
4 years ago
What is the point -slope form of a line with slope -4 that contains the point (-2,3)
Arada [10]

Answer:

y - 3 = -4 (x +2)

Step-by-step explanation:

Point slope form is

y -y1 = m(x-x1)  where m is the slope and ( x1,y1) is a point on the line

y - 3 = -4 (x - -2)

y - 3 = -4 (x +2)

5 0
3 years ago
I WILL GIVE 30 POINTS TO THOSE WHO FILL IN THE BLANKS NOOOO SCAMS!!!
Furkat [3]

Answer:

Angle A = Angle T

Angle B = Angle U

Angle C = Angle V

Step-by-step explanation:

The order that the angles are listed above shows you which angle in the first triangle corresponds to which angle in the other triangle.  It tells you triangle ABC = triangle TUV.  Since A and T are both listed first, they are equivalent.  Angles B and U are both listed second, so they correspond to each other.  And angles C and V are listed last, so they correspond to each other.

7 0
3 years ago
What is the mean, median, and standard deviation for the following set of scores: 24, 20, 16, 18, 18, 26, 22? Please show your w
MissTica

Answer:

first: Definitions

mean: the average or the most common value in a collection of numbers

(So u add all numbers and then divide the answer by how much numbers there were)

median: Is middle value.

(example:   4, 5, 6) (The median will be the middle which is 5) (But if there are even amount of numbers like this:      4, 5, 6, 7) (Then you will get the two middle numbers which in this case are 5 and 6 you add them and then divide by 2.)

standard deviation:  measures the spread of the data about the mean value

Step-by-step explanation:

Now lets get to problem!

we have numbers:

24, 20, 16, 18, 18, 26, 22

the mean will be: 144 (remember now you have to divide by 7 because there are 7 numbers.)

So it would be 20.57

Now the median:

(Since there are 7 numbers you just find the number in the middle and that would be ur median.)

24, 20, 16, 18, 18, 26, 22

median answer: 18

Like we said: The sample standard deviation measures the spread of a data distribution of the sample. It is usually used to estimate the population standard deviation

So the standard deviation will be: 3.6

I hope this helps  :)

6 0
3 years ago
Write an equation of cosine function with amplitude 2 and a period 4pi
Arisa [49]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}\\
f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}
\end{array}

\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}

now.. hmmm let's see, keeping in mind the template above

so, amplitude of 2, A=2, thus |A| = ±2, so, you can use either

and period of 4π, well, that simply means that 

\bf \cfrac{2\pi }{B}=4\pi \implies \cfrac{2\pi }{4\pi }=B\implies \cfrac{1}{2}=B\\\\
-----------------------------\\\\

\begin{array}{llll}
f(\theta)=&\pm 2cos&\left(\frac{1}{2}\theta  \right)\\
&\ \uparrow &\ \uparrow \\
&A&B
\end{array}
8 0
4 years ago
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