<span>Formula: H(t) = 56t – 16t^2
</span>
H(t) = - 16t^2 + 56t
<span><span>A.
</span>What is the height of the ball after 1 second? H
(1) = 56(1) – 16(1) ^2 = 40 pt.</span>
<span><span>B.
</span>What is the maximum height? X = - (56)/2(- 16) =
1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>
<span><span>C.
</span><span>After how many seconds will it return to the
ground? – 16t^2 + 56t = 0 - 8t =0 t = 0</span></span>
<span><span>-
</span><span>8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2
Ans: 3.5 seconds</span></span>
f(0) = 2(3)(0) = 0 ⇒ (0, 0)
f(1) = 2(3)(1) = 6 ⇒ (1, 6)
<u>rate of change from x = 0 to x = 1</u>
= 
= 
= 6
******************************************
f(2) = 2(3)(2) = 12 ⇒ (2, 12)
f(3) = 2(3)(3) = 18 ⇒ (3, 18)
<u>rate of change from x = 2 to x = 3</u>
= 
= = 6
*****************************************
Since it is the same line, they will have the same slope (aka rate of change).
Answer:
145%. The left one is 100% and then the right is the 45%.
Answer:
181/20
Step-by-step explanation:
9.05=9 5/100 = 9 1/20
9*20+1=180+1=181
181/20
Answer: 0
Step-by-step explanation:
the answer is 0
