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Elodia [21]
3 years ago
15

What is the decimal multiplier to decrease by 4.8%?

Mathematics
1 answer:
OlgaM077 [116]3 years ago
7 0

Answer:

0.952

Step-by-step explanation:

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Which of the following graphs represents a quadratic equation with roots of -5 and 2.5
tiny-mole [99]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
A ski resort claims that there is a 75% chance of snow on any given day in january and that snowfall happens independently from
lys-0071 [83]

Using the binomial distribution, it is found that the mean and the standard deviation of variable x are given as follows:

\mu = 3, \sigma = 0.87

<h3>What is the binomial probability distribution?</h3>

It is the probability of exactly <u>x successes on n repeated trials, with p probability</u> of a success on each trial.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

In this problem, we have that the parameters are given as follows:

n = 4, p = 0.75.

Hence the mean and the standard deviation are given as follows:

  • E(X) = np = 4 x 0.75 = 3.
  • \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{4 \times 0.75 \times 0.25} = 0.87

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

7 0
2 years ago
What is the greatest common factor of 22 and 2?
Snowcat [4.5K]

Answer:

2

Step-by-step explanation:

2 is 2.

22 is 2•11.

The GCF is 2.

6 0
3 years ago
Maggie is making a necklace using a 13-inch string and identical beads.
matrenka [14]

Answer:

52

Step-by-step explanation:

First find out how many beads cover 1 inch of the string which is 4 beads then multiply that number, 4, by the length of the string, 13. You should get 52.

3 0
3 years ago
Find the missing side length. Show all of your work. I'll give you the brilliant crown if you answer the question correct.
lubasha [3.4K]

Answer:

h = 6

Step-by-step explanation:

We need to use Pythagorean theorem.

h² + 8² = 10²

h² = 100 - 64 = 36

h = 6

4 0
3 years ago
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