Help ASAP!! Answer must be in radicals and in terms of pi.

Factor completely <img src="https://tex.z-dn.net/?f=3x%5E3-3x%5E2-18x" id="TexFormula1" title="3x^3-3x^2-18x" alt="3x^3-3x^2-18x

Sever21 [200]

Answer:

The answer is 3x(x - 3)(x + 2)

Step-by-step explanation:

3x³ - 3x² - 18x

Factor out 3x from the expression

We have

3x ( x² - x - 6)

Solve the terms in the bracket

We have

3x ( x² + 2x - 3x - 6)

Factor out x the expression in the bracket

We have

3x ( x ( x + 2) - 3( x + 2) )

Factor out x + 2 from the expression in the bracket

We have the final answer as

Hope this helps you.

5 0

3 years ago

The population of a certain town was 10,000 in 1990. The rate of change of the population, measured in people per year, is model

Katena32 [7]

The question is incomplete. The complete question is :

The population of a certain town was 10,000 in 1990. The rate of change of a population, measured in hundreds of people per year, is modeled by P prime of t equals two-hundred times e to the 0.02t power, where t is measured in years since 1990. Discuss the meaning of the integral from zero to twenty of P prime of t, d t. Calculate the change in population between 1995 and 2000. Do we have enough information to calculate the population in 2020? If so, what is the population in 2020?

Solution :

According to the question,

The rate of change of population is given as :

$\frac{dP(t)}{dt}=200e^{0.02t}$ in 1990.

Now integrating,

$\int_0^{20}\frac{dP(t)}{dt}dt=\int_0^{20}200e^{0.02t} \ dt$

$=\frac{200}{0.02}\left[e^{0.02(20)}-1\right]$

$=10,000[e^{0.4}-1]$

$=10,000[0.49]$

=4900

$\frac{dP(t)}{dt}=200e^{0.02t}$

$\int1.dP(t)=200e^{0.02t}dt$

$P=\frac{200}{0.02}e^{0.02t}$

$P=10,000e^{0.02t}$

$P=P_0e^{kt}$

This is initial population.

k is change in population.

So in 1995,

$P=P_0e^{kt}$

$=10,000e^{0.02(5)}$

$=11051$

In 2000,

$P=10,000e^{0.02(10)}$

$=12,214$

Therefore, the change in the population between 1995 and 2000 = 1,163.

8 0

3 years ago

Sally babysits for the Smiths every Friday. They pay her $18 for food plus $13 for each hour she works. What value represents th

Natalija [7]

Answer:

18

Step-by-step explanation:

wait check b4 you answer

3 0

4 years ago

Create a list of steps, in order, that will solve the following equation 1/4(x+5)^2-1=3

julia-pushkina [17]

Answer:

either x = -1, or x = - 9

Step-by-step explanation:

given $\frac{1}{4} (x+5)^{2} -1=3$

add one to both sides $\frac{1}{4} (x+5)^{2} =4$

im not sure which one comes first. either you multiply both the x and the 5 in the parenthesis by $\frac{1}{4}$ . or you square x and 5

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 1/4*(x+5)^2-(4)=0

Step by step solution :

Step 1 :

1 /4

Equation at the end of step 1 :

1

(— • (x + 5)2) - 4 = 0

4

Step 2 :

Equation at the end of step 2 :

(x + 5)2

———————— - 4 = 0

4

Step 3 :

Rewriting the whole as an Equivalent Fraction :

3.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 4 as the denominator :

4 4 • 4

4 = — = ———

1 4

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

(x+5)2 - (4 • 4) x2 + 10x + 9

——————— ——————— = ——

4 4

Trying to factor by splitting the middle term

3.3 Factoring x2 + 10x + 9

The first term is, x2 its coefficient is 1 .

The middle term is, +10x its coefficient is 10 .

The last term, "the constant", is +9

Step-1 : Multiply the coefficient of the first term by the constant 1 • 9 = 9

Step-2 : Find two factors of 9 whose sum equals the coefficient of the middle term, which is 10 .

-9 + -1 = -10

-3 + -3 = -6

-1 + -9 = -10

1 + 9 = 10 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 1 and 9

x2 + 1x + 9x + 9

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x+1)

Add up the last 2 terms, pulling out common factors :

9 • (x+1)

Step-5 : Add up the four terms of step 4 :

(x+9) • (x+1)

Which is the desired factorization

Equation at the end of step 3 :

(x + 9) • (x + 1)

————————————————— = 0

4

Step 4 :

When a fraction equals zero :

4.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

(x+9)•(x+1)

——————————— • 4 = 0 • 4

4

Now, on the left hand side, the 4 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

(x+9) • (x+1) = 0

Theory - Roots of a product :

4.2 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

4.3 Solve : x+9 = 0

Subtract 9 from both sides of the equation :

x = -9

Solving a Single Variable Equation :

4.4 Solve : x+1 = 0

Subtract 1 from both sides of the equation :

x = -1

Supplement : Solving Quadratic Equation Directly

Solving x2+10x+9 = 0 directly

Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

6 0

4 years ago

Solve the compound inequality 9 + 3n >= 6 or 5n < 25.

babymother [125]

$9+3n \geq 6 \ \lor \ 5n\ \textless \ 25 \\
3n \geq 6-9 \ \lor \ n \ \textless \ \frac{25}{5} \\
3n \geq -3 \ \lor \ n \ \textless \ 5 \\
n \geq \frac{-3}{3} \\
n \geq -1 \\ \\
\boxed{n \geq -1 \hbox{ or } n\ \textless \ 5} \\ \\
\hbox{answer C}$

4 0

3 years ago