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amm1812
4 years ago
5

Consider the right triangular prism given AC = 9 cm and 80 = 10 cm which statements are true regarding the prism? Check all that

apply.
The height of the prism is 10 cm

triangle DEFG is a base

triangle DFG is a lateral side the appropriate unit of measure for volume is cubic centimeters

the area of the base is 45 cm²
Mathematics
2 answers:
Levart [38]4 years ago
6 0

Answer:

The height of the prism is 10 cm

DFG is a base

The appropriate unit of measure for the volume is cubic centimeters

Step-by-step explanation:

finlep [7]4 years ago
4 0
text me for the answer
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What is the common ratio of the sequence?<br> -2,6,-18,54
aivan3 [116]

<u>ANSWER</u>

The common ratio is -3.

<u>EXPLANATION</u>

In general, the common ratio of a Geometric Sequence is given by:

r = \frac{a_{n+1}}{a_{n}}

We can find the common ratio using any two consecutive terms of the geometric sequence by dividing the subsequent term by the previous term.

The given sequence is -2,6,-18,54

Using the first two terms the common ratio is

r =  \frac{6}{ - 2}  =  - 3

We could also used the second and third terms to get

r =  \frac{ - 18}{6}  =  - 3

and so on and so forth.

Therefore the common ratio is -3.

6 0
3 years ago
There are 4 cups in a quart and 4 quarts in a gallon.how many cups are in a 5 gallon jug of water​
Ipatiy [6.2K]

Answer:

the answer is 80 cups

Step-by-step explanation:

there is 16 cups in a gallon so you just have to multiply 16 x 5 which will give your answer

5 0
3 years ago
Equation y2 = x² + 256
-Dominant- [34]
D is the answer




Hope
This helps
3 0
3 years ago
A student solves the following equation and determines that the solution is −2. Is the student correct? Explain. 3 a + 2 − 6a a2
Ganezh [65]

For this case, we have the following equation (according to the comments):

\frac{3}{a+2} - \frac{6a}{a^2-4}  = \frac{1}{a-2}

First, we factor the quadratic expression in the denominator:

\frac{3}{a+2} - \frac{6a}{(a-2)(a+2)}  = \frac{1}{a-2}

Then, we multiply both sides of the equation by (a-2) (a + 2):

\frac{3(a-2)(a+2)}{a+2} - \frac{6a(a-2)(a+2)}{(a-2)(a+2)}  = \frac{(a-2)(a+2)}{a-2}

Later, canceling similar terms we have:

3(a-2) - 6a = a+2

We do distributive property on the left side of the equation:

3a-6-6a=a+2

By grouping variables and constant terms we have:

3a - 6a -a = 2+6

Rewriting we have:

-4a=8

Finally, by clearing "a" we have:

a=-\frac{8}{4} a=-2

Note: the value of a is a extraneous solution because it makes the denominator of the original equation equal to zero.

Answer:

the student correct, but the value of a= -2 is an extraneous solution

8 0
4 years ago
Read 2 more answers
Sin(18m-12)cos(7m+2)find the value of m
insens350 [35]

Answer:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

Step-by-step explanation:


Solve for m:

-cos(7 m + 2) sin(12 - 18 m) = 0

Multiply both sides by -1:

cos(7 m + 2) sin(12 - 18 m) = 0

Split into two equations:

cos(7 m + 2) = 0 or sin(12 - 18 m) = 0

Take the inverse cosine of both sides:

7 m + 2 = π n_1 + π/2 for n_1 element Z

or sin(12 - 18 m) = 0

Subtract 2 from both sides:

7 m = -2 + π/2 + π n_1 for n_1 element Z

or sin(12 - 18 m) = 0

Divide both sides by 7:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or sin(12 - 18 m) = 0

Take the inverse sine of both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or 12 - 18 m = π n_2 for n_2 element Z

Subtract 12 from both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or -18 m = π n_2 - 12 for n_2 element Z

Divide both sides by -18:

Answer: m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

8 0
3 years ago
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