Answer: I think 13
Step-by-step explanation:
<span>Since it's even, the integral from -7 to -1 is the same as the integral from 1 to 7.
</span><span>think about
x^2
from 0..1,its 1/3
from 0..7 its 7^3/3
from -1..7 its 7^3/3+1/3
</span>
<span>from -7..-1 of x^2 its -1/3+7^3/3 to get this without integrating we just do 7^3/3-1/3 which is the integral from 0..7 minus the integral from 0..1
</span><span>So the integral from 1 to 0 f(x) dx = 5 changes to the integral from 0 to 1 f(x) dx = -5 and you add it to the integral from 0 to 7 which is 1 making -4</span>
1/2 divide by 3 or 1/[2(3)] which will be equal to 1/6
Answer:
The total surface area of a regular pyramidis the sum of the areas of its lateralfaces and its base. The general formula for thelateral surface area of a regular pyramidis where p represents the perimeter of thebase and SI the height of inclination.
U = (-2,3)
V = (3,0)
midpoint of UV
= ( (3-2)/2 , (3+0)/2 )
= ( 1/2 , 3/2)
= ( 0.5 , 1.5)
X = (0.5 , 1.5) [from fig]
midpoint of UV = X
W= (-2,-3)
V =( 3.0)
Y = ( (-2+3)/2 , (-3+0)/2 )
= (0.5 , - 1.5)
Y = ( 0.5 , -1.5) [ from fig ]
Y is the midpoint of WV
by midpoint theorem ,
UW = 2( XY )
