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3 years ago

Write the expression using a single component x^56/x^24

Mathematics

1 answer:

KiRa [710]3 years ago

4 0

Answer: x^#22

Step-by-step explanation: Cancel the common factor of

x^56 and x^24.

So your answer is x^32 I’m trying my best to explain the answer.

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8.8 - 3.4 with using mental method<br> step by step explanation

Scrat [10]

8.8-3.4=5.4

Just subtract 8-3 and 8-4 and you'll get 5.4

Hope it helps!

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Brainliest please if you found my answer helpful! :)

4 0

3 years ago

Tara scored 20 points in her first basketball game and n points in each of the next 6 games. What expression represents tara's t

Karo-lina-s [1.5K]

Answer:

20+6n

Step-by-step explanation:

Tara's point total is found by adding up the points in each game ...

20 + n + n + n + n + n + n

= 20 +6n

_____

Of course, we use multiplication to simplify repeated addition.

6 0

3 years ago

Can you please help me with 1-12? Thank you

Marysya12 [62]

Answer:

1. 18.84 in

2. 56.52 cm

Step-by-step explanation:

The circumference of a circle is the distance around the circle. Its found using the formula C = πd or C=2πr. The variable d represents the diameter or the distance from one edge of the circle to the other through the cent. The variable r represents the radius of a circle or the distance from one edge to the center. Use the formula by substituting a diameter or radius then simplify.

1. C = πd = π(6) = 3.14(6) = 18.84 in

2. C = 2πr = 2(3.14)(9) = 56.52 cm

6 0

3 years ago

Prove that 3:8 is equivalent to 12:32

Julli [10]

3 times 4 is equal to 12
8 times 4 is equal to 32
therefore 3:8 is equal to 12:32
hope this helps

3 0

3 years ago

LOTS OF POINTS GIVING BRAINLIEST I NEED HELP PLEASEE

Sidana [21]

Answer:

Segment EF: y = -x + 8

Segment BC: y = -x + 2

Step-by-step explanation:

Given the two similar right triangles, ΔABC and ΔDEF, for which we must determine the slope-intercept form of the side of ΔDEF that is parallel to segment BC.

Upon observing the given diagram, we can infer the following corresponding sides:

$\displaystyle\mathsf{\overline{BC}\:\: and\:\:\overline{EF}}$

$\displaystyle\mathsf{\overline{BA}\:\: and\:\:\overline{ED}}$

$\displaystyle\mathsf{\overline{AC}\:\: and\:\:\overline{DF}}$

We must determine the slope of segment BC from ΔABC, which corresponds to segment EF from ΔDEF.

<h2>Slope of Segment BC:</h2>

In order to solve for the slope of segment BC, we can use the following slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}} }$

Use the following coordinates from the given diagram:

Point B: (x₁, y₁) = (-2, 4)

Point C: (x₂, y₂) = ( 1, 1 )

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{1\:-\:4}{1\:-\:(-2)}\:=\:\frac{-3}{1\:+\:2}\:=\:\frac{-3}{3}\:=\:-1}$

<h2>Slope of Segment EF:</h2>

Similar to how we determined the slope of segment BC, we will use the coordinates of points E and F from ΔDEF to find its slope:

Point E: (x₁, y₁) = (4, 4)

Point F: (x₂, y₂) = (6, 2)

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{2\:-\:4}{6\:-\:4}\:=\:\frac{-2}{2}\:=\:-1}$

Our calculations show that segment BC and EF have the same slope of -1. In geometry, we know that two nonvertical lines are <u>parallel</u> if and only if they have the same slope.

Since segments BC and EF have the same slope, then it means that $\displaystyle\mathsf{\overline{BC}\:\: | |\:\:\overline{EF}}$ .

<h2>Slope-intercept form:</h2><h3><u>Segment BC:</u></h3>

The <u>y-intercept</u> is the point on the graph where it crosses the y-axis. Thus, it is the value of "y" when x = 0.

Using the slope of segment BC, m = -1, and the coordinates of point C, (1, 1), substitute these values into the <u>slope-intercept form</u> (y = mx + b) to solve for the y-intercept, <em>b. </em>

y = mx + b

1 = -1( 1 ) + b

1 = -1 + b

Add 1 to both sides to isolate b:

1 + 1 = -1 + 1 + b

2 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 2.

Therefore, the linear equation in <u>slope-intercept form of segment BC</u> is:

⇒ y = -x + 2.

<h3><u /></h3><h3><u>Segment EF:</u></h3>

Using the slope of segment EF, <em>m</em> = -1, and the coordinates of point E, (4, 4), substitute these values into the <u>slope-intercept form</u> to solve for the y-intercept, <em>b. </em>

y = mx + b

4 = -1( 4 ) + b

4 = -4 + b

Add 4 to both sides to isolate b:

4 + 4 = -4 + 4 + b

8 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 8.

Therefore, the linear equation in <u>slope-intercept form of segment EF</u> is:

⇒ y = -x + 8.

8 0

2 years ago