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nordsb [41]
3 years ago
14

Iterations question one, thanks for the help :)

Mathematics
1 answer:
Elza [17]3 years ago
4 0

Answer:

option d

13 , 173 , 29933

Step-by-step explanation:

Given in the question a function, f(x) = x² + 4

initial value x0 = -3

<h3>4 times iteration means f(f(f(x)))</h3><h3 />

First iteration

f(x0) = f(-3) = (-3)² + 4 = 13

x1 = 13

Second iteration

f(x1) = f(13) = (13)² + 4 = 173

x2 = 173

Third iteration

f(x2) = f(173) = (173)² + 4 = 29933

x3 = 29933

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Answer:

n= -2

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask ;)

6 0
3 years ago
What is the square root of 24/4
PilotLPTM [1.2K]
The square root of 24/4= 1.22474487139
3 0
3 years ago
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Find the circumference and the area of a circle with radius 3 m.
Effectus [21]

Answer:

\boxed {c= 18.84 \ m}

\boxed {a=28.26 \ m^2}

Step-by-step explanation:

We are asked to find the circumference and area of a circle with a radius of 3 meters.

<h3>1. Circumference </h3>

The circumference is the perimeter of a circle. It is calculated using the following formula:

c= \pi d

We know the radius of the circle is 3 meters, but we must find the radius. The radius is the line from the center to the circle's edge, while the diameter is the line through the center from edge to edge. Therefore, the diameter is twice the radius.

  • d= 2 r
  • d= 2 * 3 m
  • d= 6 m

The diameter is 6 meters and we are using 3.14 for pi. Substitute these values into the circumference formula.

c= (3.14)(6 \ m )

Multiply.

\bold {c= 18.84 \ m}

<h3>2. Area </h3>

The area is the size of the circle's surface. It is calculated using the following formula.

a= \pi r^2

The radius is 3 meters are we are using 3.14 for pi. Substitute these values into the area formula.

a= (3.14)(3 \ m)^2

Solve the exponent.

  • (3 m)² = (3 m)(3 m)= 9 m²

a= (3.14)(9 \ m)^2

\bold {a=28.26 \ m^2}

The circumference is 18.84 meters and the area is 28.26 square meters.

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csec%5Cleft%28x%5Cright%29%7D%7B%5Ccos%5Cleft%28x%5Cright%29%7D-%5Cfrac%7B%5Csin%5
DanielleElmas [232]

Answer:

1

Step-by-step explanation:

First, convert all the secants and cosecants to cosine and sine, respectively. Recall that csc(x)=1/sin(x) and sec(x)=1/cos(x).

Thus:

\frac{sec(x)}{cos(x)} -\frac{sin(x)}{csc(x)cos^2(x)}

=\frac{\frac{1}{cos(x)} }{cos(x)} -\frac{sin(x)}{\frac{1}{sin(x)}cos^2(x) }

Let's do the first part first: (Recall how to divide fractions)

\frac{\frac{1}{cos(x)} }{cos(x)}=\frac{1}{cos(x)} \cdot \frac{1}{cos(x)}=\frac{1}{cos^2(x)}

For the second term:

\frac{sin(x)}{\frac{cos^2(x)}{sin(x)} } =\frac{sin(x)}{1} \cdot\frac{sin(x)}{cos^2(x)}=\frac{sin^2(x)}{cos^2(x)}

So, all together: (same denominator; combine terms)

\frac{1}{cos^2(x)}-\frac{sin^2(x)}{cos^2(x)}=\frac{1-sin^2(x)}{cos^2(x)}

Note the numerator; it can be derived from the Pythagorean Identity:

sin^2(x)+cos^2(x)=1; cos^2(x)=1-sin^2(x)

Thus, we can substitute the numerator:

\frac{1-sin^2(x)}{cos^2(x)}=\frac{cos^2(x)}{cos^2(x)}=1

Everything simplifies to 1.

7 0
3 years ago
Write 24 as a prime factors what is the answer
djverab [1.8K]
Write a number as prime factors means to write the number as a product of numbers, all of which are prime. We start by checking whether the number is divisible by prime numbers, starting from the smallest prime number,2.

let's divide 24 into its factors.

first, it's even, so it must divide by 2

24=2*12

12 is also even, so it must divide by 2:


24=2*12=2*2*6

6 is also even, so it must divide by 2:


24=2*12=2*2*6=2*2*2*3

3 is not even, but it's a prime number.

so the solution is
2*2*2*3



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3 years ago
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