Answer:
the answer is A
Step-by-step explanation:
<span>standard form of a linear equation
is ax+by+c=
y=2x
y-2x=0
</span>
Answer:
The ordered pair is (1, 2) ⇒ A
Step-by-step explanation:
In the function f(x) = y
- x is the domain of the function
- y is the range of the function
- The domain is all the x-coordinates of the points lie on the graph of the function
- The range is all the y-coordinates of the points lie on the graph of the function
That means any ordered pair (x, y) satisfy the function f(x) = y, lies on the graph of the function
∵ f(x) = 2x
→ That means y = 2x
∵ x = 1
→ Substitute the value of x in the function above
∴ f(1) = 2(1)
∴ f(1) = 2
→ That means at x = 1, y = 2
∴ The ordered pair is (1, 2)
Answer:
h(8q²-2q) = 56q² -10q
k(2q²+3q) = 16q² +31q
Step-by-step explanation:
1. Replace x in the function definition with the function's argument, then simplify.
h(x) = 7x +4q
h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q
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2. Same as the first problem.
k(x) = 8x +7q
k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q
_____
Comment on the problem
In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...
h(8q² -2q) = 56q² -14q +4z
and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.
In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.
