Answer:
The size limit for 15% of of six-year-old trout is 438.52 mm.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 481 millimeters
Standard Deviation, σ = 41 millimeters
We are given that the distribution of mean length of six-year-old rainbow trout is a bell shaped distribution that is a normal distribution.
Formula:
We have to find the value of x such that the probability is 0.15
Calculation the value from standard normal z table, we have,
Thus, the size limit for 15% of of six-year-old trout is 438.52 mm.
Answer:
Use the exponential decay model with a decay factor of 0.5.
Step-by-step explanation:
Answer:
c = 30
Step-by-step explanation:
since:

once we find a c value for 10, we know that it will work for - 10 as well

we can sub in 10 to get

127 = 100 +27
32 = 30 +2
so 127 x 32 = (100 + 27) x (30+2) = (100x30) + (100x2) + (27x30) +(27x2)
= 3000+200+810+54 = 4064
second way:
127 = 100 + 27
127 x 32 = (100+27) x 32 = (100x 32) + ( 27x32) = 3200 + 864 = 4064
Answer: B ✔
Step-by-step explanation:
Volume = 4/3 × 3.14 × 7^3
Volume = 1436.03 cm^3