Answer:
i)
- <em>DA is diameter and AX is tangent to circle</em>
<u>Your answer is correct</u>
ii)
<u>Given m∠BAX = 42° and ∠DAB is complementary with BAX ⇒ </u>
<u>DC = BC ⇒ intercepted arcs are same ⇒ </u>
<u>mDC = mCB ⇒ mDCB = ∠DAB = 48° ⇒ </u>
- m∠CDB = m∠BDC = 1/2*48 = 24°
iii)
∠CBA
<u>∠CBA is supplementary with ∠ADC as opposite angles of cyclic quadrilateral (∠ADB = ∠BAX = 42°)</u>
- m∠ADC = m∠ADB + m∠CDB = 42° + 24° = 68°
- m∠CBA = 180° - m∠ADC = 180° - 68° = 112°
∠BAE
EA║CB and AB is transversal ⇒ CBA and BAE are supplementary angles:
- m∠BAE = 180° - 112° = 68°
∠DCE
- m∠DCB = 180° - m∠DAB = 180° - 48° = 132°
- m∠BCE = 180° - m∠BAE = 180° - 68° = 112°
- ∠DCE = 132° - 112° = 20°
Answer:
See attachment for answers
Step-by-step explanation:
Answer:
1. -3
2. 7
3. -2
4. 3
Step-by-step explanation:
1. idk
2. 3.2 move 3b over to get 3.2-3b-4.7=-3.3 move 4.7 over to get
3.2b-3b=4.7-3.3 now 3.2b-3b=.2b and 4.7-3.3=1.4 .2b/.2=b 1.4/.2=7 so b=7
3. 4.6y-y+4=y-1.2 now switch the 4 and the y to read 4.6y-2y=-4-1.2
2.6y=-5.2 divide both sides by 2.6 to get y=-2
4. 7.5c-2.5c+8=-7 move 8 to other side to get 7.5c-2.5c=-8-7
5c=-15 divide both sides by 5 getting c=3
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1/2 is your slope.
