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mars1129 [50]
3 years ago
8

8 inches to 24 inches

Mathematics
1 answer:
creativ13 [48]3 years ago
8 0

I'm not sure what it is you're asking here, but you can divide 24 by 8 3 times.

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Use y=mx+b. This is for slope. If you're given a coordinate such as (3,2) think of "dibble and then shoot". Go right three and up two. Hope this helps :)
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3 years ago
The end points of one diagonal of a rhombus are (-5,2) and (1,6). If the coordinates of the 3rd vertexare (-6,10), what are the
ad-work [718]
Look at the picture.

E\left(\dfrac{-5+1}{2};\ \dfrac{2+6}{2}\right)\to E\left(\dfrac{-4}{2};\ \dfrac{8}{2}\right)\to E(-2;\ 4)

\vec{BE}=[-2-(-6);\ 4-10]=[4;\ -6]

D(x;\ y)\\\\\vec{ED}=[x-(-2);\ y-4]=[x+2;\ y-4]\\\\\vec{ED}=\vec{BE}\ therefore\\\\ \ [x+2;\ y-4]=[4;\ -6]\to x+2=4\ and\ y-4=-6\\\\x=2\ and\ y=-2\\\\Answer:\ \boxed{A.\ (2;\ -2)}

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3 years ago
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Natasha2012 [34]

Answer:

Hard

Step-by-step explanation:

7 0
4 years ago
When solving the equation, which is the best first step to begin to simplify the equation?
olasank [31]

Answer:

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3 years ago
QUICK!!!HELP!!!!!!!!!!!!!!!!!!
IgorLugansk [536]

Using the normal distribution, the probability that a worker selected at random makes between $500 and $550 is: 2.15%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean mu and standard deviation sigma is given by:

Z = (X - mu)/sigma

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given as follows:

mu = 400, sigma = 50

The probability is the <u>p-value of Z when X = 550 subtracted by the p-value of Z when X = 500</u>, hence:

X = 550:

Z = (X - mu)/sigma

Z = (550 - 400)/50

Z = 3

Z = 3 has a p-value of 0.9987.

X = 500:

Z = (X - mu)/sigma

Z = (500 - 400)/50

Z = 2

Z = 2 has a p-value of 0.9772.

0.9987 - 0.9772 = 0.0215 = 2.15% probability.

More can be learned about the normal distribution at brainly.com/question/15181104

#SPJ1

6 0
2 years ago
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