All categories

3 years ago

Hi can anyone please help me I really need help please help me thank you

Mathematics

1 answer:

kirill115 [55]3 years ago

6 0

Answer:

Step-by-step explanation:

a). sphere volume =4 /3πr3 radius= diameter/2 = 10/2 R=5

4/3*3.14*5^3 = 4/3*3.14*125 = 4/3*392.5 = 523.3333333 = V=523

b). take the volume of the snow scoops and volume of the cylinder container and take 75398 and divide it by 523 which is = 144.16

c). and take the amount of snow scooped cones made (144.16) and multiply by 1.50 = 216.24 or 216

(im not 100% on any of this btw)

You might be interested in

What is 4x + 3 = 2x +7

VARVARA [1.3K]

Bring like terms together
(REMEMBER CHANGE THE SIGN WHEN MOVING ACROSS THE EQUAL SIGN i.e. - becomes + and + becomes -)
4x - 2x = 7 - 3
2x = 4
divide both sides by 2
x = 2

4 0

3 years ago

Read 2 more answers

Please help, look at the picture provided. Which function has the greatest y-intercept?

ValentinkaMS [17]

Answer:

i think its -1 box but im not sure

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Find the horizontal and vertical asymptotes of f(x). f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the

miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* Lets the meaning of vertical and horizontal asymptotes

- Vertical asymptotes are vertical lines which correspond to the zeroes

of the denominator of a rational function

- A horizontal asymptote is a y-value on a graph which a function

approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

then there is a horizontal asymptote at y = leading coefficient of the

numerator ÷ leading coefficient of the denominator

* Lets solve the problem

∵ $f(x)=\frac{6x}{x+2}$

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ The horizontal asymptote can be described by the line y = 6

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ The vertical asymptote can be described by the line x = -2

6 0

3 years ago

Read 2 more answers

Verify csc^2t-cos t sect= cot^2 t

Ymorist [56]

Rewriting the left hand side,

csc²t - cost sec t

= (1/sin²t)-(cost)(1/cost)

= 1/sin²t - 1

= 1/sin²t - sin²t/sin²t

= (1-sin²t)/sin²t

= cos²t/sin²t

= cot²t

7 0

2 years ago

Read 2 more answers

2(m + 1) = 16 full answer

Serhud [2]

Answer:

2m+2=16, then do the isolate m but doing the inverse operation of 2 which is now -2 and add that to 16 would be left with 2m=14 and 14/2 is 7 so m=7

Step-by-step explanation:

3 0

2 years ago