Question

In isosceles triangle the length of the base is twice shorter than the length of a leg. The perimeter of this triangle is 50 cm. Find the lengths of all sides.

Answer 1

The length of the base is 10 and the length of each leg is 20.

In order to find this, we can start by making the length of the base x. Now we know that the legs are twice as long, which would make them 2x. Since there are two of them, we can add x + 2x + 2x and set equal to 50 to find the value of x.

x + 2x + 2x = 50

5x = 50

x = 10

Now we can plug this in for our leg length as well to find that.

2x = Leg

2(10) = Leg

20 = leg

Answer 2

$Hey there !!$

As according to question. The lenght of the base of triangle is twice shorter than the lenght of other leg.

let us take base = x.

now we know a triangle has three legs and it is given that base is twice shorter then the leg it means the rest both legs are twice then base.

so other two legs = 2x + 2x

Now the statement is that perimeter of this triangle is 50.
As we know perimeter is equals to sum of all legs.
so x+2x+2x = 50
5x = 50
Dividing both sides with 5
x = 10

So the base is 10 cm and the other two sides are 2×10 = 20 cm. each.

HOPE IT HELPED YOU.