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4 years ago

14

Write an equation in slope-intercept form of the line passing through the points (6,62) and (5,53) The equation is y =

1 answer:

Katena32 [7]4 years ago

3 0

Answer:

y=9x+8

Step-by-step explanation:

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Another question I need help with. I've got the part where it says to rewrite as a radical expression on my paper, but I'm havin

Alik [6]

$\bf a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} 
\qquad \qquad
\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}\\\\
-------------------------------\\\\
32^{\frac{3}{5}}\implies \sqrt[5]{32^3}\qquad 
\begin{cases}
32=2\cdot 2\cdot 2\cdot 2\cdot 2\\
\qquad 2^5
\end{cases}\implies \sqrt[5]{(2^5)^3}\implies \sqrt[5]{(2^3)^5}
\\\\\\
2^3\implies 8$

4 0

4 years ago

Find the volume of a pyramid with a square base, where the perimeter of the base is 5\text{ in}5 in and the height of the pyrami

Nana76 [90]

Answer:

Volume = 1.9 in3

Step-by-step explanation:

If the perimeter of the square base is 5 inches, we have that:

Perimeter = 4 * side

5 = 4 * side

side = 1.25 in

Then, to find the volume of the pyramid, we can use the formula:

Volume = (1/3) * side^2 * height

So we have that:

Volume = (1/3) * 1.25^2 * 3.6

Volume = 1.875 in3

Rounding to nearest tenth, we have Volume = 1.9 in3

4 0

3 years ago

M3 = 64<br> What’s the value of m

Ket [755]

Answer:

m =64/3

Step-by-step explanation:

m=21 1/3 m=21.3

3 0

4 years ago

Graph the quadratic function y = 2x2 − 6x − 140. What are the solutions of the quadratic equation 0 = 2x2 − 6x − 140?

enyata [817]

Answer:

A

Step-by-step explanation:

just did the test on edg 2020

hope this helped

5 0

3 years ago

Which of the following is a root of the polynomial shown below?

Mademuasel [1]

Answer:

We conclude that option A is true as x = 1 is the root of the polynomial.

Step-by-step explanation:

Given the polynomial

$f\left(x\right)\:=\:x^2\:+\:2x^2\:-\:x-2$

Let us determine the root of the polynomial shown below.

$\:0=\:x^2\:+\:2x^2\:-\:x-2$

$0=3x^2-x-2$

switch sides

$3x^2-x-2=0$

as

$3x^2-x-2=\left(3x+2\right)\left(x-1\right)$

so the equation becomes

$\left(3x+2\right)\left(x-1\right)=0$

Using the zero factor principle

$3x+2=0\quad \mathrm{or}\quad \:x-1=0$

solving

$3x+2=0$

$3x=-2$

$\frac{3x}{3}=\frac{-2}{3}$

$x=-\frac{2}{3}$

and

$x-1=0$

$x=1$

The possible roots of the polynomial will be:

$x=-\frac{2}{3},\:x=1$

Therefore, from the mentioned options, we conclude that option A is true as x = 1 is the root of the polynomial.

3 0

3 years ago