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Angelina_Jolie [31]
4 years ago
6

Another question I need help with. I've got the part where it says to rewrite as a radical expression on my paper, but I'm havin

g trouble simplifying.

Mathematics
1 answer:
Alik [6]4 years ago
4 0
\bf a^{\frac{ n}{ m}} \implies  \sqrt[ m]{a^ n} 
\qquad \qquad
\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}\\\\
-------------------------------\\\\
32^{\frac{3}{5}}\implies \sqrt[5]{32^3}\qquad 
\begin{cases}
32=2\cdot 2\cdot 2\cdot 2\cdot 2\\
\qquad 2^5
\end{cases}\implies \sqrt[5]{(2^5)^3}\implies \sqrt[5]{(2^3)^5}
\\\\\\
2^3\implies 8
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How many perfect cubes are there between 2 to 200 ?<br> ANSWER fast
Mekhanik [1.2K]

Answer:

Three

Step-by-step explanation:

The perfect cubes between 2 to 200 are

{3}^{3}  = 27 \\  \\  {4}^{3}  = 64 \\  \\  {5}^{3}  = 125 \\

Hence, there are only three perfect cubes 27, 64 and 125 between 2 to 200.

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4 years ago
Renting a tool form Store A costs $9.75 per hour plus a fee of $188.55. Renting the same tool
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Step-by-step explanation:

6 0
3 years ago
For the equation given below, evaluate y′ at the point (−2,2)<br> xe^y−4y=2x−4−2e^2
jeka94
Implicit differentiation
chain rule is important here

I'll show the steps partially
e^y+xe^yy'-4y'=2
xe^yy'-4y'=2-e^y
y'(xe^y-4)=2-e^y
y'=\dfrac{2-e^y}{xe^y-4}
now evaluate for (-2,2)
x=-2 and y=2
y'=\dfrac{2-e^2}{-2e^2-4}
y'=\dfrac{2-e^2}{-2e^2-4}
y'=\dfrac{e^2-2}{2e^2+4}
that's it, simplest form
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