Answer:
Rotation 90 degree counterclockwise then 2 units up.
Step-by-step explanation:
Given : Quadrilateral ABCD and A'B'C'D'.
To find: What transformation were applied to ABCD to obtain A’B’C’D.
Solution: We have given
A (3,6) →→ A'(-6,5)
B( 3,9)→→ B'(-9 ,5)
C(7,9)→→C'(-9 ,9)
D(7,6)→→D'(-6,9)
By the 90 degree rotational rule : (x ,y) →→(-y ,x) and unit 2 unit up
A (3,6) →→ A'(-6,3) →→ A'(-6,3+2)
B( 3,9)→→ B'(-9 ,3)→→ B'(-9 ,3+2)
C(7,9)→→C'(-9 ,7) →→C'(-9 ,7+2)
D(7,6)→→D'(-6,7)→→D'(-6,7+2)
Therefore, Rotation 90 degree counterclockwise then 2 units up.
