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3 years ago

Which of the points A(−6, 2), B(0, 0), C(4, −2), D(−12, 6), E(−10, 10) belong to the graph of direct variation y=− 1 2 x?

Mathematics

1 answer:

vovangra [49]3 years ago

5 0

ANSWER

B(0, 0),

EXPLANATION

The given points are A(−6, 2), B(0, 0), C(4, −2), D(−12, 6), E(−10, 10).

The equation of the direction variation is

$y = - 12x$

The point that belongs the graph of the direct variation must satisfy the variation equation.

Note that the graph of direct variation equation passes through the origin therefore the point (0,0) satisfies it.

0=-12(0)

0=0

This is true

The other points do not satisfy this variation equation, hence they do not lie on its graph

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2 years ago

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On occasions you will come across two or more unknown quantities, and two or more equations

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Solve the simultaneous equations 3x + 2y = 36 (1)

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2 years ago

What is an equation in point-slope form for the line perpendicular to y = 7x + 14 that contains (3, –7)?

umka21 [38]

The equation of the perpendicular line is y + 7 = -1/7(x - 3)

<h3>How to determine the line equation?</h3>

The equation is given as

y = 7x + 14

Also, from the question

The point is given as

Point = (3, -7)

The equation of a line can be represented as

y = mx + c

Where

Slope = m

By comparing the equations, we have the following

m = 7

This means that the slope of y = 7x + 14 is 7

So, we have

m = 7

The slopes of perpendicular lines are opposite reciprocals

This means that the slope of the other line is -1/7

The equation of the perpendicular lines is then calculated as

y = m(x - x₁) +y₁

Where

m = -1/7

(x₁, y₁) = (3, -7)

So, we have

y = -1/7(x - 3) - 7

Evaluate

y = -1/7(x - 3) - 7

Add 7 to both sides

y + 7 = -1/7(x - 3)

Hence, the perpendicular line has an equation of y + 7 = -1/7(x - 3)