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2 years ago

Round 2826 to the nearest hundred.

Mathematics

1 answer:

sergij07 [2.7K]2 years ago

3 0

Answer:

2800

Step-by-step explanation:

2826 to the nearest hundred is 2800

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To avoid distortion of extreme values, a good indicator would be the A. mean. B. weighted-mean. C. mode. D. median

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To avoid distortion of extreme values, a good indicator would be the

B. median.

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3 years ago

Read 2 more answers

Find the area of each figure. Round to the nearest tenth if necessary.

natita [175]

Answer:

Solution given:

diameter(d)=6mm

base(b)=8mm

height (h)=5mm

Area of figure=area of parallelogram +area of semi circle

base*height+½π(d/2)²
8*5+½*π×(6/2)²
40+14.14
54.4mm²
Area :54.14mm²

for triangle

base[b]=6ft

height(h)=9ft

for square

length[l]=9ft

Area of figure=area of square +area of triangle

=l²+½*b*h
=9²+½*6*9
=81+27
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Area: 108ft²

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2 years ago

Josiah is buying a Christmas present for his mom. He has $24 in his saving account but needs $60 to buy the present he has in mi

olchik [2.2K]

Answer:

Step-by-step explanation:

9h + 24 = 60

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2 years ago

Hi! I need help with the attached question in calc. Thank you:)

Elena L [17]

Answer:

3π square units.

Step-by-step explanation:

We can use the disk method.

Since we are revolving around AB, we have a vertical axis of revolution.

So, our representative rectangle will be horizontal.

R₁ is bounded by y = 9x.

So, x = y/9.

Our radius since our axis is AB will be 1 - x or 1 - y/9.

And we are integrating from y = 0 to y = 9.

By the disk method (for a vertical axis of revolution):

$\displaystyle V=\pi \int_a^b [R(y)]^2\, dy$

So:

$\displaystyle V=\pi\int_0^9\Big(1-\frac{y}{9}\Big)^2\, dy$

Simplify:

$\displaystyle V=\pi\int_0^9(1-\frac{2y}{9}+\frac{y^2}{81})\, dy$

Integrate:

$\displaystyle V=\pi\Big[y-\frac{1}{9}y^2+\frac{1}{243}y^3\Big|_0^9\Big]$

Evaluate (I ignored the 0):

$\displaystyle V=\pi[9-\frac{1}{9}(9)^2+\frac{1}{243}(9^3)]=3\pi$

The volume of the solid is 3π square units.

Note:

You can do this without calculus. Notice that R₁ revolved around AB is simply a right cone with radius 1 and height 9. Then by the volume for a cone formula:

$\displaystyle V=\frac{1}{3}\pi(1)^2(9)=3\pi$

We acquire the exact same answer.

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2 years ago

The circumference of a circle is 71 π m. What is the area, in square meters? Express your answer in terms of π.

Svetach [21]

The area of the circle is 1260.25 π m^2

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2 years ago