⠀⠀⠀⠀
In questions given,One number is six more than a second number.
if second number is a
first number is a+6.
and,
four times the first is 10 less than 6 times the second.
So,
4×(a+6)=6a-10
we have to solve this.
we,get our second number =a=17.
So,
first number =a+6=17+6=23
Answer:
Step-by-step explanation:
This is an exponential equation that is solved by taking the natural log of both sides. The equation is
If we are looking for x when f(x) = 64, then
Take the natural log of both sides:
The rules of logs allows us to bring the x down in front:
Divide both sides by ln(2) to get:
Do this on your calculator to get that x = 6.
You could also have just gone right to your calculator and started raising 2 to consecutive powers starting at like 3 or 4 to eventually get that 2 to the 6th power is equal to 64, but for the basics of solving log equations, you need to know how to do this.