The time it takes an object to fall from a great height depends on the object's acceleration due
1 answer:
It will take him 3.20 seconds to reach the water
Step-by-step explanation:
The given is;
1. The formula h = g t² can be used to describe the
relationship, with t representing time (in seconds), h representing
the height of the object (in feet), and g representing the object's
acceleration due to gravity
2. The acceleration of gravity is 32 ft/s²
3. A cliff diver leaps into the water from a height of 164 feet
4. The air resistance is negligible and does not have an effect
We need to find how long will it take him to reach the water
∵ h = g t²
∵ h = 164 feet
∵ g = 32 ft/s²
- Substitute these values in the formula above
∴ 164 = (32) t²
∴ 164 = 16 t²
- Divide both sides by 16
∴ 10.25 = t²
- Take √ for both sides
∴ t = 3.20 seconds
It will take him 3.20 seconds to reach the water
Learn more:
You can learn more about speed, time and distance in brainly.com/question/13053630
#LearnwithBrainly
You might be interested in
Answer:
Probability that from a sample of 200 Indianapolis residents, fewer than 170 were rooting for the Giants in Super Bowl XLVI is 0.02385.
Step-by-step explanation:
We are given that Due to a decade-long rivalry between the Patriots and the city's own team, the Colts, most Indianapolis residents were rooting heartily for the Giants. Suppose that 90% of Indianapolis residents wanted the Giants to beat the Patriots.
Let p = % of Indianapolis residents wanted the Giants to beat the Patriots = 90%
The z-score probability distribution for proportion is given by;
Z = ~ N(0,1)
where, = % of Indianapolis residents who were rooting for the Giants in Super Bowl XLVI in a sample of 200 residents =
= 0.85
n = sample of residents = 200
So, probability that from a sample of 200 Indianapolis residents, fewer than 170 were rooting for the Giants in Super Bowl XLVI is given by = P( < 0.85)
P( < 0.85) = P(
<
) = P(Z < -1.98) = 1 - P(Z
1.98)
= 1 - 0.97615 = 0.02385
<em>The above probability is calculated using z table by looking at value of x = 01.98 in the z table which have an area of 0.97615.</em>
<em />
Therefore, probability that fewer than 170 were rooting for the Giants in Super Bowl XLVI is 0.02385.